suppressing output from user defined function

function f=fib(n);
f=ones(n,1);
for i=1:n-2;
f(i+2,1)=f(i+1,1)+f(i,1);
end;
i have this function to calculate fibbonaci sequence, but i get outputs despite having semicolons on everything.
Can anyone tell me why?

 採用された回答

Jonathan Chin
Jonathan Chin 2016 年 3 月 25 日

2 投票

When you call your function use a semi colon at the end of the function to suppress the output.
try f=fib(n) and f=fib(n); in the command line to see the results

1 件のコメント

Michael
Michael 2016 年 3 月 25 日
編集済み: Michael 2016 年 3 月 25 日
worked. i'm an idiot -_- Thanks man.

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その他の回答 (1 件)

Walter Roberson
Walter Roberson 2016 年 3 月 25 日

0 投票

You have to put a semi-colon in the line that calls fib() to prevent the default output
abc = fib(19)
fib is called and returns an expression that is assigned to the variable, but the default action for assignment is to also display the result of the assignment. You would need
abc = fib(19);
to suppress it.
This is not under the control of the called function, which does not have control by the time MATLAB makes the decision about whether to output or not.

5 件のコメント

Michael
Michael 2016 年 3 月 25 日
thanks.
Yevgeniy Gorbachev
Yevgeniy Gorbachev 2024 年 2 月 25 日
That's not the case, though. plot has an output (`Line` object) but does not display it by default. Clearly there is some way to suppress the output from the callee. I'm currently trying to do that for some custom plotting functions and I can only find answers like this.
Voss
Voss 2024 年 2 月 25 日
X = 1;
Y = 2;
custom_func(X,Y) % no output: no output shown
Z = custom_func(X,Y); % 1 output, suppressed with semicolon: output not shown
Z = custom_func(X,Y) % 1 output, unsuppressed: output shown
Z = 3
function out = custom_func(x,y)
result = x+y;
if nargout
out = result;
end
end
Yevgeniy Gorbachev
Yevgeniy Gorbachev 2024 年 2 月 25 日
@Voss Exactly the behavior I'm looking for, thank you!
Voss
Voss 2024 年 2 月 25 日
You're welcome!

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