Can regexprep be used for partial text replacements containing special characters?

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I have a text file containing the following 3 lines of data:
"028 2016 10:11:12.12345" 39.028469 -104.484128 2070
"028 2016 10:11:13.1234" 39.028404 -104.484111 2075
"028 2016 10:11:14" 39.028390 -104.484000 2080
I am attempting to use regexprep to replace the time stamp portion (in quotations) with a single numerical value. If successful, the 3 lines of data would look like this:
1 39.028469 -104.484128 2070
2 39.028404 -104.484111 2075
3 39.028390 -104.484000 2080
I'm looking for a reference in the MATLAB documentation that would indicate how to account for the quotation marks, as well as all characters between them. This is my first attempt at using regexprep and I'm not even sure this is possible.
Is there a way to utilize regexprep for this instance?
Thank you.

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Azzi Abdelmalek
Azzi Abdelmalek 2016 年 3 月 25 日
編集済み: Azzi Abdelmalek 2016 年 3 月 25 日
v=importdata('file.txt')
a=regexprep(v,'\<".+"\>','')
b=regexp(a,'\S+','match')
n=numel(b);
out=[(1:n)' str2double(reshape([b{:}],n,[]))]
  3 件のコメント
Azzi Abdelmalek
Azzi Abdelmalek 2016 年 3 月 25 日
Another alternative is
v=importdata('fic.txt')
w=num2cell(1:numel(v))'
a=cellfun(@(x,y) regexprep(x,'\<".+"\>',num2str(y)),v,w,'un',0)

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