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eliminating value out of range

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Mayank Lakhani
Mayank Lakhani 2016 年 3 月 14 日
コメント済み: Mayank Lakhani 2016 年 3 月 15 日
I have two matrix.
A = rand(8,10);
B = rand(8,41);
range = 0.5345 (y+ direction and y- direction, range of elements of A);
i want to take all elements of B which fall in the range of matrix A 's elements. The elements of B which does not fall in the range should be NaN.
  2 件のコメント
Matthew Eicholtz
Matthew Eicholtz 2016 年 3 月 14 日
編集済み: Matthew Eicholtz 2016 年 3 月 14 日
I assume the code snippet you provide is just to demonstrate the size of A and B and not exactly how you create A and B? Because "A = rand(8,10);" will not necessarily yield a range of 0.5345.
Mayank Lakhani
Mayank Lakhani 2016 年 3 月 15 日
yes, you are right.

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Image Analyst
Image Analyst 2016 年 3 月 14 日
Declare a logical variable that states when values are in range
inRange = B >= min(A(:)) & B <= max(A(:));
Now assign to nan if outside that range, as you asked:
B(~inRange) = nan;
Or you can extract only those that are in range into a new variable:
BInRange = B(inRange);
Or you can delete those that are not in range, giving a shorter B than the original:
B(~inRange) = [];

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