matrix multiplication

Assume we have the following matrix A = [ 1 2; 3 4; 5 6]; and we want to do the following multiplication
[ A(:,1)*A(:,1)';A(:,2)*A(:,2)'] without loop. So the result should be like this B =
1 3 5
3 9 15
5 15 25
4 8 12
8 16 24
12 24 36
Could you please help me with this problem.
Thanks

1 件のコメント

James Tursa
James Tursa 2012 年 1 月 28 日
Ummm ... you already did. I presume you really have a more general question in mind? Like a larger size variable? Or ...?

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 採用された回答

James Tursa
James Tursa 2012 年 1 月 28 日

0 投票

Another way:
[m n] = size(A);
Ar = reshape(A,m,1,n);
B = reshape(mtimesx(Ar,Ar,'t'),m,m*n).'
You can find mtimesx on the FEX here:
href=""<http://www.mathworks.com/matlabcentral/fileexchange/25977-mtimesx-fast-matrix-multiply-with-multi-dimensional-support</a>>
Is there a reason why you need the result stacked vertically as you have it? The last transpose is moving all of the data around in memory. You could avoid it if you stacked the results horizontally instead.

1 件のコメント

Behrouz
Behrouz 2012 年 1 月 29 日
Thanks.

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その他の回答 (1 件)

Andrei Bobrov
Andrei Bobrov 2012 年 1 月 28 日

0 投票

B = reshape(bsxfun(@times,permute(A,[1 3 2]),permute(A,[3 1 2])),size(A,1),[]).'

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