Replace values in one column in multiple cells in array
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I'm trying to replace the 5th column in each cell in a cell array with the 5th column of each cell from another cell array. I made the following function, which does this but also replaces the values in all other columns with 0. How do I do this without deleting all other values from the other columns. The function is:
function [X]=replace_cells(cell)
X={};
for i=1:length(cell)
X{i}(:,[5])=cell{i}(:,[5]);
end
4 件のコメント
Amos
2016 年 2 月 23 日
編集済み: Amos
2016 年 2 月 23 日
then I can't see why your code should not work ... if you post a full example (including test cell arrays), people can have a look at the issue
edit: wait, you shouldn't initialize X as empty cell array, but rather give it as an input to your function...
採用された回答
Amos
2016 年 2 月 23 日
Maybe try:
function [X]=replace_cells(cell,X)
for i=1:length(cell)
X{i}(:,[5])=cell{i}(:,[5]);
end
2 件のコメント
Guillaume
2016 年 2 月 23 日
編集済み: Guillaume
2016 年 2 月 23 日
Please replace the variable name cell with something that is not a matlab function. While it does not cause any problem in this short function, it is still confusing to the casual reader.
For that matter, using meaningful names for all variables would be much better. How about:
function destination = replace_cell(destination, source, column)
assert(size(destination) == size(source));
for cidx = 1:numel(source)
destination{cix}(:, column) = source{cidx}(:, column);
end
end
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