How do I plot data from a structure with time?

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Kieran Reeves
Kieran Reeves 2016 年 2 月 4 日
I have a structure with time from my scope in Simulink sent back to Matlab. I am unsure of what script code to use in Matlab to plot the data against time as I see it in the scopes in Simulink.
The structure is called Control_Logic
The signals area as follows.
How do I plot each individual signal vs time? Thanks Kieran
  2 件のコメント
Walter Roberson
Walter Roberson 2016 年 2 月 4 日
Could you show us
fieldnames(Control_Logic.signals)
and also if you could drag the divider between "values" and "dimensions" further right on the information, then you should be able to see the full information about the size of the first field; we can see it is 108350 by something but we cannot see what at the moment.
Kieran Reeves
Kieran Reeves 2016 年 2 月 4 日
Hi Walter
>> fieldnames(Control_Logic.signals)
ans =
'values'
'dimensions'
'label'
'title'
'plotStyle'
Which appear to just be the column titles
Kieran

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採用された回答

Guillaume
Guillaume 2016 年 2 月 4 日
編集済み: Guillaume 2016 年 2 月 4 日
Most likely, this will work:
plot(Control_Logic.time, [Control_Logic.signals.values])
The [Control_Logic.signals.values] concatenates the values field of the 3 signal structures together into a 108350 x 3 matrix (assuming that values is 108350 x 1).
  3 件のコメント
Guillaume
Guillaume 2016 年 2 月 4 日
subplot(2, 2, 1); plot(Control_Logic.time, Control_Logic.signals(1).values);
subplot(2, 2, 2); plot(Control_Logic.time, Control_Logic.signals(2).values);
subplot(2, 2, 3); plot(Control_Logic.time, Control_Logic.signals(3).values);
is one way to do it.
Kieran Reeves
Kieran Reeves 2016 年 2 月 4 日
Thank you so much.

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その他の回答 (1 件)

Lars Lindner
Lars Lindner 2018 年 11 月 9 日
Hi everybody, I have the exact same problem. Trying the command
plot(data.time, data.signals(1).values)
gives me the error shown in following image:
Does anybody has an idea, what I am doing wrong?
Thanks everybody and with nice greetings, Lars
  1 件のコメント
LUIS ANGEL OLVERA OLVERA
LUIS ANGEL OLVERA OLVERA 2018 年 11 月 20 日
Hi,
You have an issue using singleton dimensions, please review "squeeze"
squeeze Remove singleton dimensions.
B = squeeze(A) returns an array B with the same elements as
A but with all the singleton dimensions removed. A singleton
is a dimension such that size(A,dim)==1. 2-D arrays are
unaffected by squeeze so that row vectors remain rows.
NewArray=squeeze(data.signals(1).values)
This function will turn your initially (1,1,10161) structure to a new (10161,1) array which can be used with your time array
To graph:
plot(data.time, A)
I hope this is useful for your project!
Luis Olvera

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