Naming figures with existing filename

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10B
10B 2016 年 1 月 20 日
コメント済み: 10B 2016 年 1 月 21 日
Hello Community,
I am having trouble getting the naming of my figures right. What I want to do is use part of a variable that contains an existing file name. For example: baseFileName = IMG_1234.jpg, and I want the title for the subsequent figure to read as, 'RGB 1234'. I have tried various iterations of code, an example of which is:
figure('name', 'RGB (regexpi(baseFileName, (?<=IMG_)\d+', 'match', 'once'))', 'numbertitle', 'off');
but obviously the section referring to 'regexpi(baseFileName,...etc.' would also appear in the title which is not what I want. The regexpi line of code has worked sucessfully elsewhere so I know this is correct, but I'm struggling to insert it in to the correct part of naming the figure.
This is for a script that will be run a few times using different images and I want to store the images after with their correct ID in the title for future reference.
So, can anyone offer some useful advice please?
Regards,
10B.

採用された回答

Ilham Hardy
Ilham Hardy 2016 年 1 月 20 日
Perhaps this might works?
figT = ['RGB ' (regexpi(baseFileName, (?<=IMG_)\d+', 'match', 'once'))];
figure('name', figT, 'numbertitle', 'off');
  3 件のコメント
Ilham Hardy
Ilham Hardy 2016 年 1 月 21 日
Hello,
Apparently you've missed a colon in your example.
It should be:
figT = ['RGB ' (regexpi(baseFileName, '(?<=IMG_)\d+', 'match', 'once'))];
instead of
figT = ['RGB ' (regexpi(baseFileName, (?<=IMG_)\d+', 'match', 'once'))];
Hope this helps, IH
10B
10B 2016 年 1 月 21 日
Ah - the curse of the missing colon! (or single inverted comma). That's it, sorted perfectly. Thanks a lot for your help.

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その他の回答 (1 件)

Image Analyst
Image Analyst 2016 年 1 月 20 日
You're probably referring to the annoying feature of title where it treats the letter following an underline as a subscript. You can turn off that annoying default feature by using the 'Interpreter' option in title(), xlabel(), or ylabel():
baseFileName = 'IMG_1234.jpg';
[~, baseNameNoExtension, ~] = fileparts(baseFileName);
title(baseNameNoExtension, 'Interpreter', 'none'); % No subscript now - YAY!!!
Or if you just plain don't want the underline, replace it with a space:
baseFileName = 'IMG_1234.jpg';
[~, baseNameNoExtension, ~] = fileparts(baseFileName);
baseNameNoExtension(baseNameNoExtension == '_') = ' ';
title(baseNameNoExtension, 'Interpreter', 'none');
  1 件のコメント
10B
10B 2016 年 1 月 21 日
Do you know Image Analyst, your suggestion wasn't exactly what I was looking for, but, as it turns out is very good information in any case as I am now going to use this in the script to for generating the 'caption' title for the figure as well. Great stuff - thanks a lot for your input!

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