Split signal if there are zero values

Hello, my task is simple i want to divide my signal into number x parts, where x is when the difference between the last nonzero value and the next to be found should be greater than a threshold, T. I tried to implement this but i always get the new result to be the same, my vector is not divided into subvectors.

s1=[0,1,2,5,0,0,5,3,0,0,0,0,3,4,1,2];
 h=0;
  T=4;
     for kk=1:length(s1)-1
         if diff([s1(kk) s1(kk+1)])<T
             h=h+1;
             P{h}=[s1(kk):s1(kk+1)];
         end
     end

Any suggestion wellcomed, or shoould i use combine the find with the unique functions? thank you.

[Azzi Abdelmalek]

Can you post the expected result?

[Manolis Michailidis]

yes, for the specified T i should get 2 subvectors A=[0,1,2,5,0,0,5,3] and B=[3,4,1,2]

[Walter Roberson]

Is this referring to the difference in position or the difference in value ?

[hemalatha]

which basis you are getting the subvectors?.Because in your vector you are having 7 zeroes and the subvectors contains only 3 zeroes.how it is?

[Walter Roberson]

hemalatha, notice that the break is taken at the point where there are T zeros in a row. I suspect that is what the poster is asking about, difference in position rather than difference in value itself.

Answer 1

[goerk]

s1=[0,1,2,5,0,0,5,3,0,0,0,0,3,4,1,2];
signalID = cumsum([0 diff(s1)>4]);

nofSignals = signalID(end)+1;

for i=1:nofSignals
    P{i}=s1(signalID==i-1);
end