フィルターのクリア

Integration for a range of values with variable limits

2 ビュー (過去 30 日間)
Keelan Toal
Keelan Toal 2015 年 12 月 18 日
コメント済み: Keelan Toal 2015 年 12 月 19 日
Hi all,
I need to solve the following equation for each individual value of f where f=0:0.01:10:
The equation is for MSAR in the code below, with the intention of getting a range of RMSAR values for a given f.
K1=274350; C1=11040; K2=414000; C2=16000;
M=13200; L1=2.34; L2=2.885; K=2.310;
I=M*(K^2);
a1=46.85*(10^-4); b1=0.19;
syms f
w=f*2*pi;
B11=K1+K2-M*(w^2)+1i*w*(C1+C2);
B12=K2*L2-K1*L1+1i*w*(-C1*L1+C2*L2);
B13=-K1-1i*w*C1;
B21=K2*L2-K1*L1+1i*w*(-C1*L1+C2*L2);
B22=K1*(L1^2)+K2*(L2^2)-I*(w^2)+1i*w*(C1*L1^2+C2*L2^2);
B23=K1*L1+1i*w*C1*L1;
B31=0; B32=0; B33=1;
S1=K2+1i*w*C2;
S2=K2*L2+1i*w*C2*L2;
S3=0.975;
B(1,1)=B11; B(1,2)=B12; B(1,3)=B13;
B(2,1)=B21; B(2,2)=B22; B(2,3)=B23;
B(3,1)=B31; B(3,2)=B32; B(3,3)=B33;
S(1,1)=S1; S(2,1)=S2; S(3,1)=S3;
T=B\S;
hif=T(1,:)';
G1=a1*exp((-b1)*f);
MSARn=@(f)((abs(hif))^2).^(f^4)*G1;
iMSARn=int(MSARn,0.89*f,1.12*f);
MSAR=((2*pi)^4)*iMSARn;
RMSAR=MSAR.^0.5;
When I try running the code, it's incredibly slow. I left it going over night and it still wasn't done. So I need a more practical method as this is only a section of a larger code. Am I correct in thinking that only 'int' accepts variable integral limits? I've tried 'quad' in a loop but it still sees the limits as non-scalar:
for k=1:1:1001;
f(k)=(k-1)/100;
iMSARn(k)=quad(@PSD_Opt_int_loop,[0.89*f(k),1.21*f(k)]);
end
Thanks in advance.

採用された回答

Walter Roberson
Walter Roberson 2015 年 12 月 18 日
iMSARn(k)=quad(@PSD_Opt_int_loop, 0.89*f(k), 1.21*f(k));
Notice no []
  1 件のコメント
Keelan Toal
Keelan Toal 2015 年 12 月 19 日
That solves that problem, thanks.
However, I'm having further issues. The code runs entirely but my results are way out. Can you see any obvious issues with my code? Assuming my constants/equations are correct.
function MSARn = Func_PSD2 (f)
K1=274350; C1=11040; K2=414000; C2=16000;
M=13200; L1=2.34; L2=2.885; K=2.310;
I=M*(K^2);
a1=46.85*(10^-4); b1=0.19;
w=f*2*pi;
B11=K1+K2-M*(w.^2)+1i*w*(C1+C2);
B12=K2*L2-K1*L1+1i*w*(-C1*L1+C2*L2);
B13=-K1-1i*w*C1;
B21=K2*L2-K1*L1+1i*w*(-C1*L1+C2*L2);
B22=K1*(L1^2)+K2*(L2^2)-I*(w.^2)+1i*w*(C1*(L1^2)+C2*(L2^2));
B23=K1*L1+1i*w*C1*L1;
B31=0; B32=0; B33=1;
S1=K2+1i*w*C2;
S2=K2*L2+1i*w*C2*L2;
S3=0.975;
b11=size(B11,2);
B11p=permute(reshape(B11',1,b11,[]),[1 3 2]);
B12p=permute(reshape(B12',1,b11,[]),[1 3 2]);
B13p=permute(reshape(B13',1,b11,[]),[1 3 2]);
B21p=permute(reshape(B21',1,b11,[]),[1 3 2]);
B22p=permute(reshape(B22',1,b11,[]),[1 3 2]);
B23p=permute(reshape(B23',1,b11,[]),[1 3 2]);
S1p=permute(reshape(S1',1,b11,[]),[1 3 2]);
S2p=permute(reshape(S2',1,b11,[]),[1 3 2]);
B=zeros(3,3,b11);
B(1,1,:)=B11p; B(1,2,:)=B12p; B(1,3,:)=B13p;
B(2,1,:)=B21p; B(2,2,:)=B22p; B(2,3,:)=B23p;
B(3,1,:)=B31; B(3,2,:)=B32; B(3,3,:)=B33;
S(1,1,:)=S1p; S(2,1,:)=S2p; S(3,1,:)=S3;
T(:,:,1)=abs(B(:,:,1))\abs(S(:,:,1));
T(:,:,2)=abs(B(:,:,2))\abs(S(:,:,2));
if size(B,3)>2
T(:,:,3)=abs(B(:,:,3))\abs(S(:,:,3));
end
if size(B,3)>3
T(:,:,4)=abs(B(:,:,4))\abs(S(:,:,4));
end
if size(B,3)>4
T(:,:,5)=abs(B(:,:,5))\abs(S(:,:,5));
end
if size(B,3)>5
T(:,:,6)=abs(B(:,:,6))\abs(S(:,:,6));
end
if size(B,3)>6
T(:,:,7)=abs(B(:,:,7))\abs(S(:,:,7));
end
hif=((squeeze(T(1,:,:)))');
G1=a1*exp((-b1)*f);
MSARn=(hif.^2).*(f.^4).*G1;
end
and
clear
clc
f=zeros(1,1001); iMSARn=zeros(1,1001);
for k=1:1:1001;
f(k)=(k)/100;
iMSARn(k)=quad(@Func_PSD2,0.89*f(k),1.12*f(k));
end
MSAR=((2*pi)^4)*iMSARn;
RMSAR=MSAR.^0.5;
plot(f,RMSAR)
I'm aiming for the graph labelled 4:
But I'm getting the following:
Any suggestions?

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeNumeric Solvers についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by