redChannel = IM(:, :, 1);
greenChannel = IM(:, :, 2);
blueChannel = IM(:, :, 3);
for yourNumber = 1 : max(labelimg(:))
thisLabel = labelimg == yourNumber; % for example 2 or 3 or whatever region you want.
meanR(yourNumber) = mean(redChannel(thisLabel));
meanG(yourNumber) = mean(greenChannel(thisLabel));
meanB(yourNumber) = mean(blueChannel(thisLabel));
end
table(neigbor label)=
2 3 4 5
2 1
3 1 1
4 1 1 1
5 1 0 1 1
I got a table which show the neighbor label and I got mean rgb for each label, I just need loop through the left triangle because another part is same.
The mean value for the label is double type, how I can round to integer only?
I got the mean of each label region and then I now want to compare them.
for i=2 : max(table(:))
for j=2:max(table(:))
if(i,j+1)=1 %1 mean 2 label are neighbor
if compare(j+1,i)<=(rgb+-5) %then reassign the label
if (i>j+1) label i = label j+1 %always assign to smaller label
else label j+1 = label to i
Final result I hope to get is like this
label 4 and 5 is within(rgb+-5) with label 2 so all assign to label 2
label =
3 3 3 3 3 3
1 1 1 1 1 1
1 2 2 1 4 1
1 1 1 1 4 1
5 5 5 1 1 1
5 5 5 5 5 5
result =
3 3 3 3 3 3
1 1 1 1 1 1
1 2 2 1 2 1
1 1 1 1 2 1
2 2 2 1 1 1
2 2 2 2 2 2

 採用された回答

Walter Roberson
Walter Roberson 2015 年 12 月 6 日

0 投票

abs(meanR(j+1)-meanR(i)) <= 5 &&
abs(meanB(j+1)-meanB(i)) <= 5 &&
abs(meanG(j+1)-meanG(i)) <= 5

4 件のコメント

Tan Wen Kun
Tan Wen Kun 2015 年 12 月 6 日
編集済み: Tan Wen Kun 2015 年 12 月 6 日
This solve the problem, did not need to using compare, I forget can do like this by using absolute.
for i=2 : max(table(:))
for j=2:max(table(:))
if(i,j+1)=1 %1 mean 2 label are neighbor
if (abs(meanR(i,j+1)-meanR(i,j)) <= 5 &&
abs(meanB(i,j+1)-meanB(i,j)) <= 5 &&
abs(meanG(i,j+1)-meanG(i,j)) <= 5)
This statement true, I want to reassign label to smaller label. Below code is correct?
if (label(i,j)>label(i,j+1))
label(i,j) = label(i,j+1) %always assign to smaller label
else label(i,j+1) = label(i,j)
Walter Roberson
Walter Roberson 2015 年 12 月 7 日
編集済み: Walter Roberson 2015 年 12 月 7 日
The definition of meanR and so on that you show in your original post are indexed only by a single value, not by two values.
if(i,j+1)=1
is not valid syntax, not even if you change the = to == . You want
if table(i,j+1) == 1
You also do not want to use
for i=2 : max(table(:))
because table consists entirely of 0 and 1 so max() of it is going to be 1, and for i=2:1 is not going to do anything. You want to run i to the maximum label, not the maximum table.
Tan Wen Kun
Tan Wen Kun 2015 年 12 月 7 日
編集済み: Tan Wen Kun 2015 年 12 月 7 日
ya,it is one value for meanR, ytd I think and write wrongly
so I should use for i=2:max(label(:)) ?
label =
1 1 1 1 1
1 2 1 3 1
1 1 1 1 1
I want to made label 3 to label 2, how to do?
for i=2 : max(label(:))
for j=2:max(label(:))
if table(i,j+1)==1 %1 mean 2 label are neighbor
if (abs(meanR(j+1)-meanR(i)) <= 5 && abs(meanB(j+1)-meanB(i)) <= 5 && abs(meanG(j+1)-meanG(i)) <= 5)
if label(j+1)>i
label(j+1)=label(i);
else
label(i)=label(j+1);
end
Error in (line 122)
if (abs(meanR(j+1)-meanR(i)) <= 5 &&
abs(meanB(j+1)-meanB(i)) <= 5 && abs(meanG(j+1)-meanG(i))
<= 5)
why i got this problem?
Walter Roberson
Walter Roberson 2015 年 12 月 7 日
maxlab = max(label(:));
for i = 1 : maxlab
for j = 1 : maxlab - 1
if table(i,j+1) == 1
if abs(meanR(j+1)-meanR(i)) <= 5 &&
abs(meanB(j+1)-meanB(i)) <= 5 && abs(meanG(j+1)-meanG(i))
<= 5
if label(i, j+1) > label(i, j)
label(i, j+1) = label(i,j)
else
label(i,j) = label(i, j+1);
end
end
end
end

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その他の回答 (1 件)

Image Analyst
Image Analyst 2015 年 12 月 6 日

0 投票

The answer to "how I can round to integer only?" is to use the int32() function.

5 件のコメント

Tan Wen Kun
Tan Wen Kun 2015 年 12 月 6 日
編集済み: Tan Wen Kun 2015 年 12 月 6 日
how to compare mean value for both label? what is the function name?
Jan
Jan 2015 年 12 月 6 日
@Tan Wen Kun: The function name of what? What should the command "compare(j+1,i)<=(rgb+-5)" do? It is impossible to guess, what you want.
Tan Wen Kun
Tan Wen Kun 2015 年 12 月 6 日
I want to compare the mean value of label which is neighbor.
I want to compare whether the meanR, meanG, meanB value of label 2 and label 3 is within 5 or not? If this 3 statement true then I reassign label 3 to label 2.
Image Analyst
Image Analyst 2015 年 12 月 6 日
I have no idea what that triangular table is so I can't answer. And I don't know what reassigning labels is going to do. I think you're trying to do some kind of region growing/merging because you started out with a bad segmentation that was made worse by oversegmentation by watershed and now you're trying to fix it in a way that won't work.
Tan Wen Kun
Tan Wen Kun 2015 年 12 月 7 日
table(neigbor label)=
2 3 4 5
2 1 1 1 1
3 1 1 1 0
4 1 1 1 1
5 1 0 1 1
this table is show which label is neighbor label.
What I mean triangular is because table(2,3) is same as table(3,2) so I do not need to check twice whether their rgb value is within 5 or not.
I only need check half side only

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