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Wayne King
Wayne King 2012 年 1 月 7 日

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Hi Sara, I'm not sure what A has to do with the way you have phrased your question. The span of b is simply all scalar multiples of b. Accordingly, it's just the imaginary axis.
Or did you really mean to ask whether b is in the range of A, in other words, in the span of the columns of A? In that case, did you really mean that b = [0; 1j]?
There is a difference between the following two vector spaces, the complex numbers, C, and complex-vectors with two entries, C^2.
The columns of A are vectors in C^2. The "vector" b as you have written it is just in C.

3 件のコメント

sara s
sara s 2012 年 1 月 7 日
Hi Wayne,thanks so much for your answer
But I want to know if there is any instruction in matlab to find span and I know A is not related to my question,that is mistake :))
Wayne King
Wayne King 2012 年 1 月 7 日
Hi Sara b = [0 ; 1j] is already an orthonormal basis for its span.
sara s
sara s 2012 年 1 月 7 日
Thanks so much Wayne
Kind regards

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