deleting words from a cell array
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if I have a cell array
x={'areach';'aread';'areal';'areality';'arean';'arear';'areasoner';'areaway';'areca';'arecaceae'}
y='a'
word='areach'
How do I delete all the words from x that do not have y in the positions it appears in word
for example 'a' appears as the 1st and 4th letter of word, delete all words from dictionary that do not have 'a' as their 1st and 4th position letters. so x would become
x={'areach';'aread';'areal';'areality';'arean';'arear';'areasoner';'areaway'}
(it got rid of 'areca' and 'arecaceae)
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Mohammad Abouali
2015 年 11 月 11 日
編集済み: Mohammad Abouali
2015 年 11 月 11 日
x={'areach';'aread';'areal'; ...
'areality';'arean';'arear'; ...
'areasoner';'areaway';'areca'; ...
'arecaceae'};
y='a';
word='areach';
% This line does the trick;
x=x(cellfun(@(c) all(c(find(word==y))==y),x))
x =
'areach'
'aread'
'areal'
'areality'
'arean'
'arear'
'areasoner'
'areaway'
Note that the position 1 and 4 are not hard coded. They are defined based on the y and word
1 件のコメント
Mohammad Abouali
2015 年 11 月 16 日
編集済み: Mohammad Abouali
2015 年 11 月 16 日
you can also use
x=x(cellfun(@(c) all(c(word==y)==y),x))
i.e. without using find().
その他の回答 (1 件)
bio lim
2015 年 11 月 11 日
x={'areach';'aread';'areal';'areality';'arean';'arear';'areasoner';'areaway';'areca';'arecaceae'};
for n = 1 : length(x)
if ~strcmp(x{n}(4),'a')
x{n}=[];
end
end
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