how to remove the first 5 characters from a cell array 343x1 cell
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Hello all, I would like to remove the first few characters from every single cell (343), yet I am not much aware of how to do it. I tried to solve the problem via googling it yet could not find anything that would fit my case. The cell array is attached. Example: for "d035-117" for instance i would like to convert it into a form of "117". The first 5 characters need to be truncated. Thanks for your advices and help in advance!
2 件のコメント
Image Analyst
2022 年 12 月 7 日
@Jack you can see he accepted my answer below so I guess it worked for him.
If you have any more questions, then attach your data and code to read it in with the paperclip icon after you read this:
採用された回答
Image Analyst
2015 年 10 月 27 日
How about (untested)
for k = 1 : length(ca)
cellContents = ca{k};
% Truncate and stick back into the cell
ca{k} = cellContents(6:end);
end
5 件のコメント
Supriya Gain
2022 年 5 月 18 日
I have a folder which contains 389 CSV files. And each CSV file has a dimension of 82x1. So basically it's a 1D matrix. Now the first element (i.e. A1) of every CSV file is 'VAR'. Now I want to remove this 'VAR' and shift my matrix to the upside. That means I want to remove A1 element and shift the whole matrix from A1. How to do that.
Image Analyst
2022 年 5 月 18 日
@Supriya Gain try reading it into a table and deleting the first column
t = readtable(filename);
t = t(:, 2:end)
If that doesn't work, start a new question of your own (not here) and attach one of the CSV files there.
その他の回答 (1 件)
Jos (10584)
2015 年 10 月 27 日
編集済み: Jos (10584)
2015 年 10 月 27 日
If A is your cell-array of strings, this oneliner will do the job:
B = cellfun(@(x) x(1:end-5), A, 'un', 0)
2 件のコメント
Leone Campos
2023 年 1 月 5 日
For those who are wondering what 'un' is, it stands for 'UniformOutput'.
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