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Subscripted assignment dimension mismatch Error, How to find the cause?
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Good afternoon,
I'm stuck again on what I think is a minor problem but I can't seem to figure how to get around it.
I keep getting the Subscripted assignment dimension mismatch.
Error in CR (line 168) LOC7(2:4,k) = OB(1,idx)
Loc7 is 4 x 37 double and OB is 2 x 37 double.
k should run to 37 but keeps stopping at fourteen.
I've used this method on other data and it works fine, I'm confused about where/ why and how to fix this error.
Any suggestions or thought are very much appreciated!
Thank you for any time you can spare!!
LOC7 = LOC6;
for k = 1:size(OBLOC6,2)
if LOC6(1,k)~=0
[idx] = find(OB(2,:)==LOC6(1,k))
if ~isempty(idx)
if LOC7(2,k) == 0
LOC7(2:4,k) = OB(1,idx)
end
end
end
end
1 件のコメント
Jan
2015 年 10 月 26 日
Please use code formatting and avoid leading spaces for standard text. I've edited your question to improve the readability this time.
回答 (1 件)
Jan
2015 年 10 月 26 日
If idx is not a scalar this line must fail:
LOC7(2:4,k) = OB(1,idx)
Then you have a [2 x 1] array on the left hand side, and a [1 x N] vector on the right.
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