Variable change over time

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Amaral
Amaral 2015 年 10 月 8 日
コメント済み: Star Strider 2015 年 10 月 9 日
Hello friends!
I have three 2d points (the xx values represents time instants between [0;1] and yy represents rotation values): initial = [0 , 0]; middle = [0.5 , 1.5409]; final = [1 , 3.0817];
I'm looking to do an interpolation of the remaining points for each 0.1 in the xx axis. The easiest way is to do a linear interpolation using linspace, but in this case i dont want to use evenly spaced values. What i want to do have is to have lower yy values on the first 4 intervals ([0 ; 0.4]) and higher yy values on the last 4 ([0.6 ; 1]), like the one i represented on the image below with orange color (blue represents the linear interpolation). Any ideas? Thanks for helping! :)

採用された回答

Star Strider
Star Strider 2015 年 10 月 8 日
I would fit it with a Logistic function, simply because it looks like one.
  4 件のコメント
Amaral
Amaral 2015 年 10 月 9 日
Yes it is! Thanks a lot friend! :)
Star Strider
Star Strider 2015 年 10 月 9 日
My pleasure!

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その他の回答 (1 件)

Robert Dylans
Robert Dylans 2015 年 10 月 8 日
編集済み: Robert Dylans 2015 年 10 月 8 日
If there's no particular requirement for the function's data, other than it "looks like" that kind of shape, you can use a formula similar to this:
x=0:0.01:1;
y=3.0817*(1-(1-((2*x).^3)./8).^5);
plot(x,y)
This was just a formula I happened to be using for something else, that has a similar curve fit. I'm sure there are many with similar functions. Note that this one only works for values of x in the range of [0 1]
  1 件のコメント
Amaral
Amaral 2015 年 10 月 9 日
That seems to be doing what i want! Thanks a lot! :)

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