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Linear Interpolation and Cubic Spline Interpolation

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Michael
Michael 2011 年 12 月 8 日
Well I'm stuck on this problem which says: Using the data Volume = 1:6 Pressure = [2494, 1247, 831, 623, 499, 416] and linear interpolation to create an expanded volume-pressure table with volume measurements every 0.2m^3. Plot the calculated values on the same graph with the measured data. Show the measured data with circles and no line and the calculated values with a solid line. Repeat using cubic spline interpolation. Any help or tips would be greatly appreciated!!!

回答 (1 件)

the cyclist
the cyclist 2011 年 12 月 8 日
My tip is to carefully read
>> doc interp1
  3 件のコメント
Jan
Jan 2011 年 12 月 8 日
The Pressure values are the measurements. If you are in doubt, you can try all (both) possibilities and look, what's comming out.
the cyclist
the cyclist 2011 年 12 月 8 日
To tie things to the documentation a bit: "x" and "Y" are your Volume and Pressure data, respectively. "xi" are volume points (every 0.2 m^3) where you want to obtain interpolated pressure values (which will be the "yi" output).

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