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How to initialize an empty vector/null vector in matlab,

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Sai
Sai 2015 年 8 月 8 日
コメント済み: Walter Roberson 2015 年 8 月 8 日
I would like to transfer the u_real(n) value to the u_Q1(n) array. But, when I am trying to compile it is telling me that the variable u_Q1 is undefined. How can I define that variable as empty vector.
u_real=real(u);
v_real=real(v);
temp = 0;
for n = 1:100
if and(u_real(n)>0,v_real(n)>0)
if n == temp + 1
u_real(n) == u_Q1(n);
v_real(n) == v_Q1(n);
temp = n;
else
d = n-temp;
u_real(n) == u_Q1(n-d+1);
v_real(n) == v_Q1(n-d+1);
temp = n-d+1;
end
end
end
  2 件のコメント
James Tursa
James Tursa 2015 年 8 月 8 日
"... transfer the u_real(n) value to the u_Q1(n) array ..."
Looks to me like you are doing the opposite. What is your actual intent?
Sai
Sai 2015 年 8 月 8 日
Ahh..! I'm soo dumb, I just found that.. Sorry but my intention was to transfer the u_real(n) value to a vector. Can you suggest me. Thanks.

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Walter Roberson
Walter Roberson 2015 年 8 月 8 日
  1 件のコメント
Walter Roberson
Walter Roberson 2015 年 8 月 8 日
u_real(n) == u_Q1(n);
means to compare u_real(n) to u_Q1(n) for equality and have a value of 0 if they are not exactly equal and 1 if they are exactly equal. Then once that logical 0 or 1 is calculated, the result is discarded because the ";" at the end of the line means not to display the value of the expression.
You probably want to use assignment = instead of comparing values ==

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