How to find the equation of a graph after getting Xdata and Ydata ?
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x = [0 1 2 3 4 5 6 7 8 9 10];
y = [4 3 4 7 12 19 28 39 52 67 84];
% How to find the function y = F(x) ??
% because I need for example to know
% if x = 1.5
% y = ??
% the solution should be something regarding regression.
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その他の回答 (2 件)
Brendan Hamm
2015 年 8 月 7 日
The easiest way would be to use the polynomial fitting functions. For this you need to know what order polynomial to fit, so visualize the data:
plot(x,y)
The data you gave looks quadratic, so let's find the coefficients for a second order polynomial:
coeff = polyfit(x,y,2);
Now evaluate the polynomial at a new value of x:
xNew = 1.5;
yNew = polyval(coeff,xNew);
plot(xNew,yNew,'r*');
5 件のコメント
Brendan Hamm
2015 年 8 月 7 日
For more complex linear models you can take a look at fitlm in the Statistics and Machine Learning Toolbox.
Joel Sande
2015 年 8 月 7 日
Brendan Hamm
2015 年 8 月 10 日
If you want to assume the data you had was from a one dimensional polynomial, then this works fine (as interp1 is doing a 1 dimensional linear interpolation). On the other hand if you want the requirement that, "the solution should be something regarding regression", then polyfit or fitlm would be the appropriate choice.
Joel Sande
2015 年 8 月 11 日
Joel Sande
2016 年 4 月 18 日
Walter Roberson
2015 年 8 月 7 日
one of the infinite number of solutions is:
x = [0 1 2 3 4 5 6 7 8 9 10];
y = [4 3 4 7 12 19 28 39 52 67 84];
pp = polyfit(x, y, length(x)-1);
y1_5 = polyval(pp, 1.5)
Another of the infinite solutions is:
x = [0 1 2 3 4 5 6 7 8 9 10];
y = [4 3 4 7 12 19 28 39 52 67 84];
y1_5 = 19;
It is not mathematically possible to distinguish between these two solutions as to which one is "more correct".
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