How to find common centroids?

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Ivan Shorokhov
Ivan Shorokhov 2015 年 7 月 8 日
回答済み: Guillaume 2015 年 7 月 8 日
Given: I have coordinates of 5 center points. For example:
centroids =
[] [156,140]
[114,167][156,141]
[117,172][157,142]
[155,140][]
[153,141][]
Want: I want to find nearest common centroid. Such as:
Common_centroids =
[156,140]
[156,141]
[157,142]
[155,140]
[153,141]
Currently done:
% remove blank cells matlab
centroids = centroids_test2'; centroids(cellfun(@isempty,centroids)) = [];
% convert the contents of a cell array into a single matrix.
centroid =[cell2mat(centroids')];
% find mean value
mean_centroid = round(mean(centroid));
% x coordinates of cenroid
centroid_x = centroid(:,1);
% y coordinates of cenroid
centroid_y = centroid(:,2);
%find x values more than mean
index1 = find(repmat(mean_centroid(1),length(centroid),1) < centroid_x);
% find y values less than mean
index2 = find(repmat(mean_centroid(2),length(centroid),1) > centroid_y);
Common_centroids = [centroid_x(index1),centroid_y(index2)];
Here is the output:
Common_centroids =
156 140
156 141
157 142
155 140
153 141
As you can see code itself is not robust at all, because I have to specify which mean value to find.
Needed: So I'm wondering, if there are any other better and more efficient way of doing it?
[ACKNOWLEDGMENTS]
Thanks in advance for any help.
I will vote for all your answers.
[MATLAB version]
R2014a

採用された回答

Guillaume
Guillaume 2015 年 7 月 8 日
This is one way of doing it:
centroids = {[], [156 140]; [114 167], [156 141]; [117 172], [157 142]; [155 140], []; [153 141], []};
cmedian = median(vertcat(centroids{:}));
%convert centroids with a 3d array with [inf inf] for missing centroids
infcentroids = centroids;
infcentroids(cellfun(@isempty, centroids)) = {[inf inf]};
infcentroids = reshape(cell2mat(infcentroids), size(infcentroids, 1), 2, []);
%calculate square of euclidean distance from median:
edist = sum(bsxfun(@minus, infcentroids, cmedian).^2, 2);
%find minimum in each row:
[~, closest] = min(edist, [], 3);
%use that to index centroids:
common_centroids = cell2mat(centroids(sub2ind(size(centroids), (1:size(centroids, 1))', closest)))

その他の回答 (1 件)

Thorsten
Thorsten 2015 年 7 月 8 日
I is not exactly clear to me what you want to achieve. To order C depending on distance to the mean:
C{1} = [];
C{2} = [156,140];
C{3} = [114,167];
C{4} = [156,141];
C{5} = [117,172];
C{6} = [157,142];
C{7} = [155,140];
C{8} = [];
C{9} = [153,141];
C = reshape(cell2mat(C), 2, [])';
[distCmean ind] = sort(sum((C - repmat(mean(C), [size(C,1) 1])).^2, 2));
C(ind)
  1 件のコメント
Ivan Shorokhov
Ivan Shorokhov 2015 年 7 月 8 日
編集済み: Ivan Shorokhov 2015 年 7 月 8 日
@Thorsten, I want to find median value (of center points) and then according to that median value find nearest coordinates in the array.
Something like this:
median_x = median(sort(centroid_x));
median_y = median(sort(centroid_y));
[row1, col2] = find(centroid_x>median_x*0.9 & centroid_x<median_x*1.1) % find x values more than mean
[row3, col4] = find(centroid_y>median_y*0.9 & centroid_y<median_y*1.1) % find x values more than mean
Common_centroids2 = [centroid_x(row1),centroid_y(row3)]

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