フィルターのクリア

Another way instead of for loop

1 回表示 (過去 30 日間)
muhammad ismat
muhammad ismat 2015 年 6 月 17 日
編集済み: Walter Roberson 2015 年 6 月 17 日
I have this code
for i = 1:34
for j = 1:i % <-- Note the 1:i instead of 1:n
s(i,j) = abs(z(i,ind(j))-z(j,ind(i)))/(z(i,ind(j))+z(j,ind(i)));
s(j,i) = s(i,j)
end
end
but it is very slow, so i want another way instead of for loop.
  2 件のコメント
Christiaan
Christiaan 2015 年 6 月 17 日
Dear Muhammad, What would you like to acchieve? Kind regards
muhammad ismat
muhammad ismat 2015 年 6 月 17 日
i have a matrix 10 x 10
then i make a cluster to previous matrix then i want calculate eq
(z(i,ind(j))-z(j,ind(i)))/(z(i,ind(j))+z(j,ind(i)))
to each point in the matrix
where ind cluster no that a point belong to, z is the distance from point to a cluster

サインインしてコメントする。

回答 (0 件)

カテゴリ

Help Center および File ExchangeStatistics and Machine Learning Toolbox についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by