how to seperate even or odd elements and make row vectors from a matrix
3 ビュー (過去 30 日間)
古いコメントを表示
Muhammad Usman Saleem
2015 年 5 月 28 日
コメント済み: Mohazam Awan
2017 年 3 月 22 日
Hi everyone I am going to attempt that question : Write a function called separate_by_two that takes a matrix A of positive integers as an input and returns two row vectors. The first one contains all the even elements of A and nothing else, while the second contains all the odd elements of A and nothing else, both arranged according to column-‐major order of A. You are not allowed to use for-‐loops or while-‐loops.
I am using that code
function[odd_ones even_ones]=separate_by_two(A)
odd_fin = rem(A,2) ~= 0;
number_odd = A(odd_fin);
number_even = A(~odd_fin);
odd_ones=number_odd';
even_ones=number_even';
end
but getting that error
Problem 7 (separate_by_two):
Feedback: Your program made an error for argument(s) 1
What correction i needed in my code? thanks in advance for assistance..
0 件のコメント
採用された回答
Roger Stafford
2015 年 5 月 28 日
The only error I see is that your returned values are in reversed order. According to the statement of the problem you should have
function[even_ones, odd_ones] = separate_by_two(A)
1 件のコメント
Mohazam Awan
2017 年 3 月 22 日
This function gives only odd numbers as output. mine one gives even ones
その他の回答 (2 件)
charu sharma
2015 年 8 月 20 日
Your order of output is not correct as they asked even ones in first output. You can refer this for different solution of same ques: http://farzicoders.blogspot.in/2015/08/write-function-called-separatebytwo.html
0 件のコメント
Mohazam Awan
2017 年 3 月 22 日
function [ even,odd ] = result( A ) %UNTITLED Summary of this function goes here % Detailed explanation goes here [r,c]=size(A); x=1; y=1; for i=1:r for j=1:c if rem(A(i,j),2)==0 even(x)=A(i,j); x=x+1; else if rem(A(i,j),2)~=0; odd(x)=A(i,j); y=y+1; end end end
end end
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Creating and Concatenating Matrices についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!