how to sort histogram generated count and corresponding gray value.. pls help
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m=imread('ll.bmp');
[count,gray]=imhist(m);
the answer is:
i want to sort the count and corresponding gray value..
and delete the zero count values answer like this..
0 件のコメント
採用された回答
ARJUN K P
2015 年 5 月 20 日
編集済み: ARJUN K P
2015 年 5 月 20 日
1 件のコメント
Image Analyst
2015 年 5 月 20 日
It does the same thing that I did but combined the counts and gray level arrays into a single 2D array (which we didn't know you wanted to do).
その他の回答 (2 件)
Image Analyst
2015 年 5 月 18 日
Don't use gray as a variable name - it's the name of a built in function that creates a colormap, and you just blew it away.
I don't know why you need to, but to get rid of array elements with zero counts
[count, grayLevels]=imhist(m);
rowsToDelete = count == 0;
count(rowsToDelete) = [];
grayLevels(rowsToDelete) = [];
5 件のコメント
Image Analyst
2015 年 5 月 18 日
To sort in reverse order, simply use fliplr()
count = fliplr(count)
grayLevels = fliplr(grayLevels);
Image Analyst
2015 年 5 月 19 日
% Sort count in descending order.
[sortedCounts, sortIndexes] = sort(count, 'descend');
% Sort grayLevels the same way.
grayLevels = grayLevels(sortIndexes);
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