Read and process a Fortran90 binary file

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Carola Forlini
Carola Forlini 2024 年 11 月 21 日 18:30
編集済み: Les Beckham 約1時間 前
Hi,
I have a Fortran90 code where a variable called 'stream' is defined such that it stores certain variable every nstep:
open(19,file='stream',form='UNFORMATTED',position='append')
if(mod(NSTEP,100).eq.0)then
write(19)NSTEP,U,W,zeta
endif
How can I properly read the file in Matlab for postprocessing?
FYI, the fortran code is built with double precision.
Thank you
  3 件のコメント
Walter Roberson
Walter Roberson 2024 年 11 月 21 日 20:21
The FORTRAN runtime system embeds the record boundaries in the data by inserting an INTEGER*4 byte count at the beginning and end of each unformatted sequential record during an unformatted sequential WRITE. The trailing byte count enables BACKSPACE to operate on records.
Carola Forlini
Carola Forlini 約24時間 前
I am attaching an extract of the file.
NSTEP is an integer = 2000
U, W, zeta are matrices = 32x512
Thank you

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回答 (2 件)

Les Beckham
Les Beckham 2024 年 11 月 21 日 19:14
編集済み: Les Beckham 2024 年 11 月 21 日 19:15
It would help to have a sample file to experiment with.
Nevertheless, assuming that the write call that you have shown is the only thing that writes to this file in your Fortran code, I would suggest something like this using fread and reshape:
fid = fopen('your_file_name.ext', 'rb');
A = fread(fid);
data = reshape(A, 4, numel(A)/4)';
nstep = A(:,1);
U = A(:,2);
W = A(:,3);
zeta = A(:,4);
Note that you might run into endian-ness issues if your Fortran code runs on a different architecture than your Matlab is running on. See the documentation for the machinefmt option to fread if necessary.
  5 件のコメント
Les Beckham
Les Beckham 約6時間 前
Thanks for adding the example.
Can you clarify what you mean by this?
NSTEP is an integer = 2000
Especially the "= 2000" part. Is that just an example of a possible value? What is the size of this integer (number of bits)?
Also, are U, W, and zeta double precision (64 bit) floating point 2-d arrays with the given size?
Carola Forlini
Carola Forlini 約5時間 前
I apologize for the misunderstanding.The size of NSTEP is 32 bit.
U, W, zeta are single precision (32 bit) of size N1×N3, with N1=32 and N3=512.

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Les Beckham
Les Beckham 約1時間 前
編集済み: Les Beckham 約1時間 前
In light of the additional variable size information and sample file provided by the OP, and the information from Walter about Fortran inserting record boundary byte counts at the beginning and end of each record written with an unformatted sequential WRITE, here is a fresh answer.
Note that this makes an assumption about the order the data is written (column major order). If this assumption is not correct, the inner for loop will need to be modified accordingly.
Hopefully this is close enough to get you where you need to go.
filenames = unzip('stream.zip')
filenames = 1x1 cell array
{'stream'}
fid = fopen(filenames{1}, 'rb');
% start/stop byte counts (4 bytes each) + NSTEP (4 bytes) + U, W, zeta (3*32*512*4 bytes)
recordSize = 2*4 + 4 + 3*32*512*4;
fseek(fid, 0, 'eof'); % seek to the end of the file
nBytes = ftell(fid); % find number of bytes in the file
frewind(fid); % go back to the beginning of the file
nRecords = nBytes / recordSize;
% preallocate
nStep = zeros(nRecords, 1); % column vector
U = zeros(3, 512, nRecords); % 3D arrays
W = zeros(3, 512, nRecords);
zeta = zeros(3, 512, nRecords);
for iRecord = 1:nRecords
fseek(fid, 4, 'cof'); % skip begin record byte count field
nStep(iRecord) = fread(fid, 1, 'integer*4');
for iRow = 1:3
U(iRow, :, iRecord) = fread(fid, 512, 'real*4');
W(iRow, :, iRecord) = fread(fid, 512, 'real*4');
zeta(iRow, :, iRecord) = fread(fid, 512, 'real*4');
end
fseek(fid, 4, 'cof'); % skip end record byte count field
end
fclose(fid); % close the file
whos nStep U W zeta % check variable sizes
Name Size Bytes Class Attributes U 3x512x21 258048 double W 3x512x21 258048 double nStep 21x1 168 double zeta 3x512x21 258048 double
plot(nStep); % make a plot see if nStep makes sense
grid on
Well, I don't know what your NSTEP should look like, but I would have expected a monotonically increasing count. So, either I made a mistake, or there is some additional information needed. It does appear that the size information you gave is either correct, or just coincidentally came out to be an integer divisor of the file size.

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