# plot

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Baba 2011 年 11 月 17 日
i have a column of data that has 100 points I also have a time column which only has 10 points basically data was sampled at 10Hz, but my time vector contains time value for every 10th sample.
How would I plot this? I run into a problem since the vectors are of different size.
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Baba 2011 年 11 月 17 日
i'm thinking i can add aditional time points in my time matrix
to make it's length equal to data matrix.
I have:
time=[1,2,3,4,5,6,7,8,9,10]
I need:
time=[1,1.1,1.2,1.3,1.4........10]
not sure how to do that either.
Walter Roberson 2011 年 11 月 17 日

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### 回答 (1 件)

bym 2011 年 11 月 17 日
use interp1 to resample your time vector to match the data vector
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Baba 2011 年 11 月 18 日
seems that there should be a way to create n empty spaces between each matrix element and then fill them in.
Walter Roberson 2011 年 11 月 18 日
There is no method of creating empty spaces in a vector.
Note that if interp1() is used, use the 'linear','extrap' options.
You will also have to calculate the data point endpoints. But if you have already gone through the trouble of figuring out the endpoints, then you might as well use linspace()
Use the code from your other thread, but for the Time values, instead of passing in your 200159 and so on, pass in
Time = datenum(str2num(YourTimes.'));
and use the datetick suggestion,
datetick('x','HH:MM:SS.FFF')

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