How can I flip the top area of the peak that is going down?

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Lizan
Lizan 2015 年 5 月 5 日
コメント済み: Image Analyst 2015 年 5 月 5 日
Hi, I would like to flip the part of the peak that goes gown so its pointed upward. I want there to be a space between the data where the top-points are to mark that this was the end-points and that the top peak goes upward instead of downward.. how can you do this?

回答 (1 件)

Image Analyst
Image Analyst 2015 年 5 月 5 日
For one such section, this should work (untested):
peakValue = max(signal);
index1 = find(signal > (peakValue - 0.001), 1, 'first')
index2 = find(signal > (peakValue - 0.001), 1, 'last');
signal(index1:index2) = 2 * peakValue - signal(index1:index2);
  2 件のコメント
Lizan
Lizan 2015 年 5 月 5 日
編集済み: Lizan 2015 年 5 月 5 日
Can you comment on what you are doing in this line:
2 * peakValue - signal(index1:index2)
Image Analyst
Image Analyst 2015 年 5 月 5 日
It's basically finding the distance between the max (top of the box) and the signal below the top of the box. Maybe if I did it more explicitly like this
delta = abs(peakValue - signal)
% Now add the delta to a vertical offset of peakValue
newSignal = peakValue + delta
but if you do the math you get
newSignal = peakValue + peakValue - signal
newSignal = 2 * peakValue - signal
So that's how I got the formula.

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