フィルターのクリア

read columns on command

1 回表示 (過去 30 日間)
Ghazi
Ghazi 2024 年 6 月 9 日
コメント済み: Voss 2024 年 6 月 11 日
what he mean it here and how I write the command :
  1 件のコメント
Image Analyst
Image Analyst 2024 年 6 月 9 日
Who is "he"? I have no idea what "read columns on command" means. Who or what is doing the commanding? And where are the columns? Is there some matrix with some columns?
What is Inflation1? Is it a function, script, or data? In line 2, you seem to indicate it's another m-file but you did not include it. Then in line 6 you treat it as if it's a vector of data, not a function.
I'm afraid there is just not enough information for anyone to give an answer.
If still have questions, then attach your data and code to read it in with the paperclip icon after you read this:

サインインしてコメントする。

採用された回答

Voss
Voss 2024 年 6 月 9 日

To access data from a table use curly braces {} with two subscripts or dot indexing, as in

inflation = diff(Inflation1{:,1}) ./ Inflation1{1:end-1,1} * 100;

or

inflation = diff(Inflation1.inflation) ./ Inflation1.inflation(1:end-1) * 100;

https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-table.html

  2 件のコメント
Ghazi
Ghazi 2024 年 6 月 11 日
wooow I want cry, thank you bro I love you so much .
Voss
Voss 2024 年 6 月 11 日
You're welcome!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

タグ

製品


リリース

R2024a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by