getting function as an argument of function
37 ビュー (過去 30 日間)
古いコメントを表示
hi, i am writing a matlab script that take function f which is a function of x and y and evaluate function f for some values of x and y. however i cannot get function, in my following code, f is seen as an array not a function. how can i get f. how can i evaluate at some points?
thanks.
function backEuler(f,x0,y0,h,N)
x(1)=x0;
y(1)=y0;
for i=1:N
x(i+1)=x(i)+h;
y_temp=y(i)+h*x(i)*x(i);
y(i+1)=y(i)+h*f(x(i+1),y_new);
end
plot(x,y);
end
0 件のコメント
採用された回答
Naz
2011 年 11 月 13 日
Let's say your function is f(x,y)=2x+y. You need to create this function prior you send it to your backEuler:
f=@(x,y)2*x+y;
backEuler(f,2,3,0,0);
The above lines go into the Command Window. Now, your backEuler function could be a separate file .m-function:
function backEuler(f,x0,y0,h,N)
x(1)=x0;
y(1)=y0;
for i=1:N
x(i+1)=x(i)+h;
y_temp=y(i)+h*x(i)*x(i);
y(i+1)=y(i)+h*f(x(i+1),y_new);
end
plot(x,y);
end
Just file->new->function, paste the above script and save it as backEuler (make sure that matlab does not have the function with the same name). Also, to use this function you need to set matlab to a current folder. That's it.
1 件のコメント
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Get Started with MATLAB についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!