# fourier transform ans amplitude

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Erkan 2024 年 2 月 26 日
コメント済み: Hassaan 2024 年 2 月 26 日
Hi everyone, good work, why is the converted signal divided by sqrt(n)^2 when finding P values ​​after the Fourier transformation of the gaussian pulse on the matlab website?
Fs = 44100; % Sampling frequency
T = 1/Fs; % Sampling period
t = -0.5:T:0.5; % Time vector
L = length(t); % Signal length
X = 1/(0.4*sqrt(2*pi))*(exp(-t.^2/(2*(0.1*1e-3)^2)));
n = 2^nextpow2(L);
Y = fft(X,n);
f = Fs*(0:(n/2))/n;
P = abs(Y/sqrt(n)).^2; %???

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### 採用された回答

Hassaan 2024 年 2 月 26 日
Dividing by sqrt(n)^2 after performing the FFT on a Gaussian pulse or any signal in MATLAB is a normalization step to ensure that the signal's power or energy is consistently represented across the time and frequency domains, adhering to Parseval's theorem. This step is crucial for accurate signal analysis and interpretation in various scientific and engineering applications.
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##### 2 件のコメントなしを表示なしを非表示
Erkan 2024 年 2 月 26 日
Thank you for your answer. I will contact you with a problem I am trying to resolve.
Hassaan 2024 年 2 月 26 日
You are welcome!

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