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How do I graphic

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Arturo
Arturo 2024 年 2 月 19 日
コメント済み: Dyuman Joshi 2024 年 2 月 19 日
Hellos Im new in matlab and I have no idea how to graphic
I want to graphic the ecuation
eqn = (-3+3*x)/x <= 0
sol = solve(eqn,x,'returnconditions',true)
fplot(sol,[-5 5])
I doesn't understand how use this command
And Im not very good in English
Thaks, Have a nice day
  1 件のコメント
Dyuman Joshi
Dyuman Joshi 2024 年 2 月 19 日
"And Im not very good in English"
Please write in your native language and use a translator, so that we precisely understand what you want to do.

サインインしてコメントする。

回答 (2 件)

VBBV
VBBV 2024 年 2 月 19 日
eqn = @(x) (-3+3*x)./x <= 0
eqn = function_handle with value:
@(x)(-3+3*x)./x<=0
fplot(eqn,[-5 5])

Sulaymon Eshkabilov
Sulaymon Eshkabilov 2024 年 2 月 19 日
The given inequality does not have explicit solution. Therefore, by ignoring analytical constraints, these can be obtained:
syms x
% Define EQN:
EQN = (3*x-3)/x <= 0;
% Solve:
SOL = solve(EQN, x, 'returnconditions', true, 'IgnoreAnalyticConstraints', true);
% Solution and Conditions
Solution = SOL.x
Solution = 
x
Conditions = SOL.conditions
Conditions = 
% Plot the inequality solution
fplot(Solution, [-5, 5], 'DisplayName', '(3*x-3)/x <= 0')

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