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I need to repeat a periodic signal

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ALOUI
ALOUI 2023 年 11 月 8 日
コメント済み: Walter Roberson 2023 年 11 月 11 日
The function is
f(t) = -t/2 if -2<=t<0
f(t) = t if 0<=t<1
f(t) = 1 if 1<=t<2
The periode is 4
and it has to be repeated from -10 to 10

回答 (2 件)

Image Analyst
Image Analyst 2023 年 11 月 8 日
This looks like a homework problem. If you have any questions ask your instructor or read the link below to get started:
Obviously we can't give you the full solution because you're not allowed to turn in our code as your own.
Hint: linspace to generate t, and repmat to make additional copies of a vector.
Use masking to get the ranges of indexes for t and don't use (t) when assigning f, use the mask, like
t = linspace(..................); % You finish it
f = zeros(1, numel(t)); % Initialize
indexesToAssign = (-2 <= t) & (t < 0); % Get logical vector (mask) of where these indexes are.
f(indexesToAssign) = -t/2;
% Similar for the two other ranges.

Walter Roberson
Walter Roberson 2023 年 11 月 8 日
Hint:
syms t
F(t) = piecewise(-2 <= t & t < 0, 1, 0 <= t & t < 1, 2, 1 <= t & t < 2, 3)
F(t) = 
fplot(F, [-10 10]); ylim([-1 4])
G = F(mod(t,4)-2)
G = 
fplot(G, [-10 10]); ; ylim([-1 4])
This tells us that if you can construct f(t) for one period of t, then you can extend it to an indefinite number of periods using mod
  3 件のコメント
Paul
Paul 2023 年 11 月 11 日
I don't think the expression for G is correct. G should overlay F in the range -2<t<2.
syms t
F(t) = piecewise(-2 <= t & t < 0, 1, 0 <= t & t < 1, 2, 1 <= t & t < 2, 3);
G(t) = F(mod(t,4)-2);
figure
fplot([G F],[-10 10],'ShowPoles','off')
ylim([0 4])
Walter Roberson
Walter Roberson 2023 年 11 月 11 日
Good catch, @Paul
syms t
F(t) = piecewise(-2 <= t & t < 0, 1, 0 <= t & t < 1, 2, 1 <= t & t < 2, 3);
G(t) = F(mod(t+2,4)-2);
figure
fplot([G F],[-10 10],'ShowPoles','off')
ylim([0 4])

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