using find function for char

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sermet
sermet 2015 年 4 月 16 日
編集済み: Guillaume 2015 年 4 月 16 日
line =
10 L1 L2 L5 C1 C2 P2 C5 S1 S2# / TYPES OF OBSERV
Name Size Bytes Class
line 1x81 162 char
%I need to use find function for each character in line. For example, I need to know which column is L1 or L2.

採用された回答

Guillaume
Guillaume 2015 年 4 月 16 日
編集済み: Guillaume 2015 年 4 月 16 日
Do you actually want to find which column of the string where L1 and L2 are, or if L1 is the second element and L2 the third?
If the former, then use Michael's answer. If the latter, then the best thing to do would be to split the string at the whitespaces then use strcmp:
line = '10 L1 L2 L5 C1 C2 P2 C5 S1 S2# / TYPES OF OBSERV';
splitline = strsplit(line);
L1idx = find(strcmp(splitline, 'L1'))
L2idx = find(strcmp(splitline, 'L2'))
  4 件のコメント
Guillaume
Guillaume 2015 年 4 月 16 日
I cannot reproduce your problem with the example given. My answer gives me 2 and 3 as output.
Can you find out the ASCII value of the extra characters, as it's not obvious what they are from your comment. You can get the ASCII value of a character by converting it to double, eg:
c = 'A';
asciival = double(c) %should return 65

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その他の回答 (1 件)

Michael Haderlein
Michael Haderlein 2015 年 4 月 16 日
line='10 L1 L2 L5 C1 C2 P2 C5 S1 S2';
strfind(line,'L2')
ans =
13

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