Error in parfor (First argument must be scalar.)

I am getting error in parfor as

First argument must be scalar.

in my code i use

parpool(4)

parfor i=1:l

where l is a scalar

when i use just for i=1:l and disbles parpool

the program runs just fine

what i am missing here?

[Bhooshan]

Error using sym/factor (line 51)

First argument must be scalar

Error in mtp (line 17)

parfor i=1:l

is the exact error

Answer 1

[Walter Roberson]

The error is not on the parfor line. The error is in the call to factor() that is somewhere in your parfor loop

[Sam Marshalik]

@Bhooshan: Can you show the line of code where you are calling factor?