フィルターのクリア

Error using sin in my code

4 ビュー (過去 30 日間)
Lan
Lan 2023 年 9 月 19 日
コメント済み: Lan 2023 年 9 月 19 日
I keep getting error using sin and Not enough input arguments. I'm not sure what I did wrong here
x = z + (1/s).*sin.*(s*r0*t);

採用された回答

Dyuman Joshi
Dyuman Joshi 2023 年 9 月 19 日
sin is not a variable that you are multiplying with s*r0*t, it is a function which needs input arguements to provide an output.
So, remove the element-wise multiplication sign in between sin and the parenthesis, and it should work (Assuming variables have compatible sizes for the operations performed)
%Corrected
x = z + (1/s).*sin(s*r0*t);
  1 件のコメント
Lan
Lan 2023 年 9 月 19 日
Thank you both so much. It worked!

サインインしてコメントする。

その他の回答 (1 件)

Walter Roberson
Walter Roberson 2023 年 9 月 19 日
The .* operator is element-by-element multiplication. Your code is asking to evaluate the token sin and multiply the result by (s*r0*t) . But sin as a token is a request to evaluate the sin function with no parameters, which is a problem because sin() needs to be passed one parameter.
If you want to take the sine of something, you need sin(EXPRESSION) such as sin(s*r0*t)
  1 件のコメント
Lan
Lan 2023 年 9 月 19 日
Thank you!

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by