# Incorrect datetime UTCLeapSeconds conversion

10 ビュー (過去 30 日間)
James Tursa 2023 年 8 月 7 日
コメント済み: James Tursa 2023 年 8 月 9 日
I am working with leap second data, and as part of the calculations I did this for a particular leap second:
dt1 = datetime(1972,6,30,23,59,60,'TimeZone','UTCLeapSeconds')
dt1 = datetime
1972-06-30T23:59:60.000Z
dt2 = datetime(dt1,'TimeZone','UTCLeapSeconds')
dt2 = datetime
1972-06-30T23:59:59.000Z
dt2.TimeZone
ans = 'UTCLeapSeconds'
dt1 - dt2
ans = duration
00:00:01
Well, you can see what happened. Even though the input and output time zones are both 'UTCLeapSeconds', the datetime( ) function has changed the time of this and jumped backwards 1 second. So to get around this I am forced to write code like this:
if( isequal(dt1.TimeZone,'UTCLeapSeconds') )
dt2 = dt1
else
dt2 = datetime(dt1,'TimeZone','UTCLeapSeconds')
end
dt2 = datetime
1972-06-30T23:59:60.000Z
dt1 - dt2
ans = duration
00:00:00
Looks like a bug to me, but does someone have another explanation for why this might be happening?

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### 回答 (1 件)

Cris LaPierre 2023 年 8 月 7 日

Potentially a bug, which you can report here: https://www.mathworks.com/support/contact_us.html
It looks like you have applied the time zone twice. You can do this instead:
dt1 = datetime(1972,6,30,23,59,60,'TimeZone','UTCLeapSeconds')
dt1 = datetime
1972-06-30T23:59:60.000Z
dt2 = dt1
dt2 = datetime
1972-06-30T23:59:60.000Z
dt2.TimeZone
ans = 'UTCLeapSeconds'
dt1 - dt2
ans = duration
00:00:00
##### 2 件のコメントなしを表示なしを非表示
James Tursa 2023 年 8 月 7 日
I submitted a bug report.
James Tursa 2023 年 8 月 9 日
TMW has replied that this bug will be fixed in the R2023b.

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