Reshape 1D to 3D array
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I have a 1D array (365x1) that I need to reshape into a 3D array (365x1x1) to divide into 3D array (365x721x1440). What's the most efficient means of accomplishing this task?
回答 (1 件)
the cyclist
2023 年 8 月 5 日
MATLAB arrays implicitly have length-1 dimensions after the defined dimensions. For example
% Define 365x1 array
M = rand(365,1);
% Length in 3rd dimension
size(M,3)
% Length in 31st dimension
size(M,31)
Regarding how that ends up being (365x721x1440), you'll need to provide more detail.
4 件のコメント
DGM
2023 年 8 月 6 日
編集済み: DGM
2023 年 8 月 6 日
I think we're getting confused by the suggestion of "reshaping". The way it appears to me, reshaping A is not necessary. It appears as this is simply a misunderstanding how to make array sizes compatible for arithmetic operations. Consider the example:
A = (1:4).' % a column vector
B = 2*ones(4,4,2) % a 3D array with the same page height
% you could expand A to have the same size as B
% A = repmat(A,[1 4 2]);
% but it's not necessary
A./B
So long as the arrays are compatibly-sized along their non-singleton dimensions, you should be able to perform elementwise arithmetic without explicitly expansion. If you were running a version older than R2016b, the recommended method would be to use bsxfun() instead of repmat().
Of course, I might be interpreting the question wrong.
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