Histogram normalisation: a question about terminology
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num_bins = 30; % <-- note: I specify the "number of bins" and not the "bin width", which can be different from 1
% Case 1
histcounts(X,num_bins,'Normalization','probability');
histogram(X,'NumBins',num_bins,'Normalization','probability');
% Case 2
histcounts(X,num_bins,'Normalization','pdf');
histogram(X,'NumBins',num_bins,'Normalization','pdf');
Do I understand correctly that
- For Case 1, I get the "Relative Frequency Histogram" or an "empirical estimate of the Probability Mass Function"?
- For Case 2, - where I divide by the bin widths as well -, I get the an "empirical estimate of the Probability Density Function"?
回答 (1 件)
Satwik Samayamantry
2023 年 7 月 14 日
Hi Sim,
Yeah you got it right. Your understanding for both cases is correct.
3 件のコメント
Steven Lord
2023 年 8 月 1 日
See the description of the Normalization name-value argument on either of the histogram or histcounts documentation pages. It describes exactly what the Values property of the histogram or the first output of the histcounts function represent.
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