Sampling Time and oscillator

3 ビュー (過去 30 日間)
TeraWatt
TeraWatt 2023 年 6 月 6 日
回答済み: William Rose 2023 年 6 月 6 日
I have this system that it is sampled at every 2 us. It is a model that represent a FPGA implementation (which sampling time is 8ns). 2us was selected to speed up the simulation process. The model has got an oscillator that generates a ramp with period of (60*12)^(-1), where 60 is the AC frequency, and with a final peak value of 50/60, see below the ramp generated by the oscillator
This oscillator is supposed to intercept the point =50/60 at the end of its period ( = 1388.88 us), but this number is not multiple of the sampling frequency (2us) which then results in a small error that is amplified later in the system.
What Can I do in this case?. (so as to avoid this un-sync of the oscilaltor ramp and the clock frequency)
Thanks in advance for your comments

採用された回答

William Rose
William Rose 2023 年 6 月 6 日
"What Can I do in this case?"
  1. You can ignore the small variation in the peak heights. Does it matter?
  2. You can choose a sampling frequency that is an integer multiple of the ramp frequency. The ramp frequency is 1200 Hz, and your sampling rate is 500 KHz. For example, you could use a sampling rate of 480 KHz (), or 500.4 KHz (), etc. The sample y-values at the corners may not be exactly 0 and 5/6, depending on the phase angle of the sampling, relative to the phase angle of the sawtooth, but the y-values will all be the same, if you do that.
Good luck with your work.

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeSimulink についてさらに検索

製品


リリース

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by