Calculating N-th Element Of A Sequence
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function m = seq( x )
n=[(1:x);(1:x)];
if x==1
n(1,1)=2;
end
if x==2
n(1,2)=3;
end
n(1,x)=(1-seq(x-1))./seq(x-1)+seq(x-2);
m=n(1,x);
end
I am get a stack overflow error, what am I doing wrong?
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回答 (1 件)
Image Analyst
2015 年 4 月 12 日
You're recursing in too deeply - calling it too many times. Your function does not appear to have any "end" condition where it will "back out" of this really deep recursion you're doing, like a line at the start that says something like if x <= 0 return or something like that. Think about it a little, and you'll figure it out.
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