interp3 problem

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Liyin
Liyin 2011 年 10 月 27 日
I have a dataset as below, named it as "a" in Matlab.
46.567 -111.28 2423.2 -1.2006
45.883 -110.93 2231.1 0.7962
46.783 -109.52 1844.0 2.898
46.667 -110.33 2316.5 -0.21062
46.800 -110.68 1966.0 0.12335
45.70 -110.45 1456.0 7.9804
45.767 -111.15 1398.0 2.0
46.917 -110.85 2258.6 -0.39873
46.583 -111.27 2026.9 1.20
46.117 -110.47 1981.2 3.4545
46.083 -110.43 2468.9 0.11388
45.867 -110.93 1996.4 1.9115
46.783 -110.62 2468.9 -1.4
46.90 -110.90 1996.4 0.71936
the first column are Lat, Lon, Elevation and temperature. Now I want to use these data to do the interp3 in matlab. I write the code:
% original data
x=a(:,2);
y=a(:,1);
z=a(:,3);
[X,Y,Z]=meshgrid(x,y,z);
[r,m,n]=size(X);
V=zeros(r,m,n);
for i=1:r
V(:,:,i)=a(i,4);
end
% the location for interp3 U_lat=46.958346;
D_lat=46.891312;
L_lon=-110.907516;
R_lon=-110.836179;
xi=L_lon:0.0005:R_lon;
yi=D_lat:0.0005:U_lat;
zi=1950:5:2500;
[Xi,Yi,Zi]=meshgrid(xi,yi,zi);
% do the interp3
Vi=Vi=interp3(X,Y,Z,V,Xi,Yi,Zi);
and error show as:
??? Error using ==> interp3 at 172 X, Y, and Z must be monotonic vectors or arrays produced by MESHGRID.
I don't know if the data organization of X,Y,Z,V,Xi,Yi and Zi is right or not. It always shows this error message. Any help is greatly appreciated! Thanks!

回答 (1 件)

Honglei Chen
Honglei Chen 2011 年 10 月 27 日
For interp3 to work, the data must be in a grid. However, from the data you show, it seems that they are not really sampled in a grid, i.e., the data is not always sampled in the same Lat, Lon, and Altitude. In this case, you may want to try TriScatteredInterp, somewhat like this.
F = TriScatteredInterp(x,y,z,v)
Vi = F(Xi,Yi,Zi)
check the doc for details.
doc TriScatteredInterp
HTH
  1 件のコメント
Liyin
Liyin 2011 年 11 月 8 日
It did works and finish the interpolation. But I am not sure the results is right or not. I want to display the F with plot3. But it fails. Another question is, which factor determine the accuracy of the results? the number of points? Thanks!

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