0 投票

I am trying to add zeros diagonally in this matrix so it should become 23*23 matrix. But with my program it becomes 24*22 matrix. Please help to resolve the code.
close all; clear all; clc;
A= [0 0 0 1 0 -1 0 -1 -1 0 1 -1 0 0 1 -1 0 1 0 1 -1 0
0 1 1 1 0 0 -1 0 0 0 1 -1 1 -1 -1 1 0 -1 0 -1 1 0
-1 -1 0 0 0 0 1 0 1 0 0 -1 1 1 -1 1 0 -1 1 -1 1 0
1 -1 0 -1 0 -1 -1 0 0 -1 1 0 0 0 -1 1 -1 0 -1 -1 0 1
0 1 -1 0 0 -1 1 -1 -1 -1 1 0 0 0 0 -1 0 0 -1 1 0 0
1 0 0 1 0 -1 -1 0 0 0 1 -1 0 0 -1 1 -1 0 -1 -1 1 1
-1 0 -1 0 1 0 1 0 1 0 -1 -1 1 1 0 0 0 0 1 1 0 0
0 0 -1 0 0 0 1 0 1 0 0 1 -1 0 1 0 -1 1 1 -1 1 -1
1 0 0 0 -1 0 0 1 1 -1 -1 -1 0 0 -1 -1 -1 0 0 -1 1 0
1 0 1 0 1 0 0 1 0 1 1 -1 1 0 -1 0 0 0 0 -1 -1 0
0 0 -1 -1 0 0 0 -1 0 -1 1 1 0 1 -1 1 -1 -1 -1 -1 0 0
0 -1 -1 -1 1 0 0 -1 0 0 0 1 1 0 -1 1 0 0 -1 -1 0 1
0 0 1 0 -1 0 -1 0 0 1 -1 -1 0 -1 0 -1 0 -1 1 1 1 1
-1 0 0 1 1 0 -1 -1 0 -1 -1 1 -1 -1 0 0 1 0 1 1 0 1
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 -1 0 -1 1 0 0 1 0 0 -1
0 -1 0 -1 -1 0 0 -1 0 0 0 -1 1 1 0 1 0 0 -1 -1 0 0
-1 0 -1 -1 1 0 0 1 0 1 0 -1 1 1 1 -1 0 -1 0 0 -1 -1
-1 0 0 1 0 -1 -1 -1 0 -1 -1 1 -1 0 0 0 0 -1 1 1 1 1
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 1 0 0 1 0 0 1 1 1 -1
1 1 -1 0 -1 0 -1 1 0 1 -1 -1 -1 0 1 0 -1 -1 0 1 0 -1
0 -1 1 1 0 0 -1 -1 1 1 0 -1 -1 1 0 -1 1 0 -1 0 1 0
0 -1 -1 0 1 0 0 1 0 1 0 0 -1 1 0 1 1 0 -1 0 -1 -1
1 1 -1 1 -1 0 0 0 -1 1 0 0 -1 0 -1 -1 -1 0 1 1 1 1];
S = size(A)+[1,0];
B = zeros(S);
B(~eye(S)) = A;

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VBBV
VBBV 2023 年 5 月 7 日
移動済み: VBBV 2023 年 5 月 9 日
Ran in:
Ran in:
close all; clear all; clc;
A= [0 0 0 1 0 -1 0 -1 -1 0 1 -1 0 0 1 -1 0 1 0 1 -1 0
0 1 1 1 0 0 -1 0 0 0 1 -1 1 -1 -1 1 0 -1 0 -1 1 0
-1 -1 0 0 0 0 1 0 1 0 0 -1 1 1 -1 1 0 -1 1 -1 1 0
1 -1 0 -1 0 -1 -1 0 0 -1 1 0 0 0 -1 1 -1 0 -1 -1 0 1
0 1 -1 0 0 -1 1 -1 -1 -1 1 0 0 0 0 -1 0 0 -1 1 0 0
1 0 0 1 0 -1 -1 0 0 0 1 -1 0 0 -1 1 -1 0 -1 -1 1 1
-1 0 -1 0 1 0 1 0 1 0 -1 -1 1 1 0 0 0 0 1 1 0 0
0 0 -1 0 0 0 1 0 1 0 0 1 -1 0 1 0 -1 1 1 -1 1 -1
1 0 0 0 -1 0 0 1 1 -1 -1 -1 0 0 -1 -1 -1 0 0 -1 1 0
1 0 1 0 1 0 0 1 0 1 1 -1 1 0 -1 0 0 0 0 -1 -1 0
0 0 -1 -1 0 0 0 -1 0 -1 1 1 0 1 -1 1 -1 -1 -1 -1 0 0
0 -1 -1 -1 1 0 0 -1 0 0 0 1 1 0 -1 1 0 0 -1 -1 0 1
0 0 1 0 -1 0 -1 0 0 1 -1 -1 0 -1 0 -1 0 -1 1 1 1 1
-1 0 0 1 1 0 -1 -1 0 -1 -1 1 -1 -1 0 0 1 0 1 1 0 1
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 -1 0 -1 1 0 0 1 0 0 -1
0 -1 0 -1 -1 0 0 -1 0 0 0 -1 1 1 0 1 0 0 -1 -1 0 0
-1 0 -1 -1 1 0 0 1 0 1 0 -1 1 1 1 -1 0 -1 0 0 -1 -1
-1 0 0 1 0 -1 -1 -1 0 -1 -1 1 -1 0 0 0 0 -1 1 1 1 1
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 1 0 0 1 0 0 1 1 1 -1
1 1 -1 0 -1 0 -1 1 0 1 -1 -1 -1 0 1 0 -1 -1 0 1 0 -1
0 -1 1 1 0 0 -1 -1 1 1 0 -1 -1 1 0 -1 1 0 -1 0 1 0
0 -1 -1 0 1 0 0 1 0 1 0 0 -1 1 0 1 1 0 -1 0 -1 -1
1 1 -1 1 -1 0 0 0 -1 1 0 0 -1 0 -1 -1 -1 0 1 1 1 1];
size(A)
ans = 1×2
23 22
S = size(A)+ [0 1]
S = 1×2
23 23
B = zeros(S);
B(~eye(S)) = A
B = 23×23
0 1 -1 1 0 1 -1 0 -1 0 -1 -1 1 0 0 -1 0 0 0 -1 -1 1 0 0 0 1 -1 1 -1 0 -1 1 0 -1 -1 -1 1 1 -1 -1 -1 0 -1 1 0 0 0 0 0 -1 0 0 0 -1 -1 0 0 0 1 0 0 -1 0 -1 1 1 -1 0 1 -1 1 0 0 1 1 0 -1 -1 0 1 0 0 -1 -1 -1 1 0 0 1 1 1 0 1 -1 1 1 0 -1 0 -1 1 0 -1 0 -1 -1 -1 0 1 -1 0 0 -1 0 1 0 -1 0 1 0 0 0 0 -1 0 -1 -1 -1 1 0 0 -1 0 -1 0 -1 1 0 1 1 0 0 0 -1 0 0 1 1 1 0 1 1 1 -1 0 0 0 -1 -1 1 -1 -1 0 -1 -1 0 0 0 0 0 0 1 -1 0 -1 1 0 1 1 -1 -1 -1 -1 0 0 0 0 0 0 0 -1 -1 0 -1 1 0 -1 1 0 1 1 0 0 1 -1 0 0 1 0 -1 1 0 -1 1 0 -1 0 1 0 -1 -1 0 0 -1 0 0 1 1 0 0

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Walter Roberson
Walter Roberson 2023 年 5 月 7 日
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0 投票

Ran in:
Your A is 23 x 22. You add 1 row and 0 columns to that to get B of size 24 x 22.
A= [0 0 0 1 0 -1 0 -1 -1 0 1 -1 0 0 1 -1 0 1 0 1 -1 0
0 1 1 1 0 0 -1 0 0 0 1 -1 1 -1 -1 1 0 -1 0 -1 1 0
-1 -1 0 0 0 0 1 0 1 0 0 -1 1 1 -1 1 0 -1 1 -1 1 0
1 -1 0 -1 0 -1 -1 0 0 -1 1 0 0 0 -1 1 -1 0 -1 -1 0 1
0 1 -1 0 0 -1 1 -1 -1 -1 1 0 0 0 0 -1 0 0 -1 1 0 0
1 0 0 1 0 -1 -1 0 0 0 1 -1 0 0 -1 1 -1 0 -1 -1 1 1
-1 0 -1 0 1 0 1 0 1 0 -1 -1 1 1 0 0 0 0 1 1 0 0
0 0 -1 0 0 0 1 0 1 0 0 1 -1 0 1 0 -1 1 1 -1 1 -1
1 0 0 0 -1 0 0 1 1 -1 -1 -1 0 0 -1 -1 -1 0 0 -1 1 0
1 0 1 0 1 0 0 1 0 1 1 -1 1 0 -1 0 0 0 0 -1 -1 0
0 0 -1 -1 0 0 0 -1 0 -1 1 1 0 1 -1 1 -1 -1 -1 -1 0 0
0 -1 -1 -1 1 0 0 -1 0 0 0 1 1 0 -1 1 0 0 -1 -1 0 1
0 0 1 0 -1 0 -1 0 0 1 -1 -1 0 -1 0 -1 0 -1 1 1 1 1
-1 0 0 1 1 0 -1 -1 0 -1 -1 1 -1 -1 0 0 1 0 1 1 0 1
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 -1 0 -1 1 0 0 1 0 0 -1
0 -1 0 -1 -1 0 0 -1 0 0 0 -1 1 1 0 1 0 0 -1 -1 0 0
-1 0 -1 -1 1 0 0 1 0 1 0 -1 1 1 1 -1 0 -1 0 0 -1 -1
-1 0 0 1 0 -1 -1 -1 0 -1 -1 1 -1 0 0 0 0 -1 1 1 1 1
0 -1 -1 0 1 0 -1 -1 0 -1 0 0 1 0 0 1 0 0 1 1 1 -1
1 1 -1 0 -1 0 -1 1 0 1 -1 -1 -1 0 1 0 -1 -1 0 1 0 -1
0 -1 1 1 0 0 -1 -1 1 1 0 -1 -1 1 0 -1 1 0 -1 0 1 0
0 -1 -1 0 1 0 0 1 0 1 0 0 -1 1 0 1 1 0 -1 0 -1 -1
1 1 -1 1 -1 0 0 0 -1 1 0 0 -1 0 -1 -1 -1 0 1 1 1 1];
S = size(A)+[0,1];
B = zeros(S);
B(~eye(S)) = A;
B
B = 23×23
0 1 -1 1 0 1 -1 0 -1 0 -1 -1 1 0 0 -1 0 0 0 -1 -1 1 0 0 0 1 -1 1 -1 0 -1 1 0 -1 -1 -1 1 1 -1 -1 -1 0 -1 1 0 0 0 0 0 -1 0 0 0 -1 -1 0 0 0 1 0 0 -1 0 -1 1 1 -1 0 1 -1 1 0 0 1 1 0 -1 -1 0 1 0 0 -1 -1 -1 1 0 0 1 1 1 0 1 -1 1 1 0 -1 0 -1 1 0 -1 0 -1 -1 -1 0 1 -1 0 0 -1 0 1 0 -1 0 1 0 0 0 0 -1 0 -1 -1 -1 1 0 0 -1 0 -1 0 -1 1 0 1 1 0 0 0 -1 0 0 1 1 1 0 1 1 1 -1 0 0 0 -1 -1 1 -1 -1 0 -1 -1 0 0 0 0 0 0 1 -1 0 -1 1 0 1 1 -1 -1 -1 -1 0 0 0 0 0 0 0 -1 -1 0 -1 1 0 -1 1 0 1 1 0 0 1 -1 0 0 1 0 -1 1 0 -1 1 0 -1 0 1 0 -1 -1 0 0 -1 0 0 1 1 0 0

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Haya Ali
Haya Ali
2023 年 5 月 7 日

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2023 年 5 月 9 日

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