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How to calculate the duty cycle of a time signal in a for loop?

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Susan
Susan 2023 年 3 月 14 日
コメント済み: Susan 2023 年 3 月 16 日
Hi All,
I have multiple time signals and like to compute their duty cycles automatically within a "for loop". For example the duty cycle of the following signal is 74.29%. The signal is attached and the sample rate is 15360000.
Assume I have a bunch of these signals. How can I calculate the ratio of the pulse width (duration of the on state) to the pulse period (the total duration of an on-and-off state) for each signal in a for loop?
Thanks in advance!

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Walter Roberson
Walter Roberson 2023 年 3 月 14 日
load waveform
wr = real(waveform);
wi = imag(waveform);
subplot(2,1,1); plot(wr); ylabel('real');
subplot(2,1,2); plot(wi); ylabel('imag');
mr = movmedian(wr, 5);
mi = movmedian(wi, 5);
mean(abs(mr)<0.01) * 100
ans = 74.2301
mean(abs(mi)<0.01) * 100
ans = 74.4255
  9 件のコメント
Walter Roberson
Walter Roberson 2023 年 3 月 15 日
We can tell from the graphs that the only part of the signal this is "repeatable" is the zeros.
You can do things like
%newer file
load waveform
wr = real(waveform(:).');
wi = imag(waveform(:).');
maskr = abs(wr) < 1e-3;
stopsr = strfind([maskr 0], [1 1 0]) + 2;
mean(~maskr(stopsr(2):stopsr(end-1)-1)) * 100
ans = 77.2091
maski = abs(wr) < 1e-3;
stopsi = strfind([maski 0], [1 1 0]) + 2;
mean(~maski(stopsi(2):stopsi(end-1)-1)) * 100
ans = 77.2091
This measures for the signal starting from end of the second stretch of zeros (so skipping the first pulse). But you can see it made little difference (gave a lower duty cycle in fact.)
To go much beyond that you would need a more explicit definition of what should be skipped.
Susan
Susan 2023 年 3 月 16 日
@Walter Roberson I see. Thanks again for your help. Appreciate it.

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