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calculate differentiation with large coefficient

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Cholisina
Cholisina 2023 年 3 月 9 日
編集済み: Dyuman Joshi 2023 年 3 月 9 日
Please help me
I'm trying to solve differential equation with this script using diff, but the coefficient result appear as a big series of number. How can I simplified it the coefficient?
omeganol=2.5;
E=50;
I=30;
L=600;
syms x
y=omeganol/(120*E*I*L)*(-x^5+2*600^2*x^3-600^4*x)
y = 
ydif=diff(y)
ydif = 

回答 (3 件)

Dyuman Joshi
Dyuman Joshi 2023 年 3 月 9 日
編集済み: Dyuman Joshi 2023 年 3 月 9 日
Use sym() to get accurate values.
The ideal approach would be to use sym() on every unique number.
omeganol=2.5;
E=50;
I=30;
L=600;
syms x
y=omeganol/sym(120*E*I*L)*(-x^5+2*600^2*x^3-600^4*x)
y = 
ydif=diff(y)
ydif = 

Sulaymon Eshkabilov
Sulaymon Eshkabilov 2023 年 3 月 9 日
Here is a bit improved solution:
omeganol=2.5;
E=50;
I=30;
L=600;
syms y(x)
y(x)=vpa(omeganol/(120*E*I*L)*(-x^5+2*600^2*x^3-600^4*x))
y(x) = 
ydif=diff(y(x))
ydif = 

Arka
Arka 2023 年 3 月 9 日
Hi,
MATLAB offers a function named simplify, which can help simplify different algebraic expressions.
omeganol=2.5;
E=50;
I=30;
L=600;
syms x
y1=simplify(omeganol/(120*E*I*L)*(-x^5+2*600^2*x^3-600^4*x))
y1 = 
y=omeganol/(120*E*I*L)*(-x^5+2*600^2*x^3-600^4*x)
y = 
Since the fraction is irrational, MATLAB prefers keeping it in the fraction form instead of converting it to scientific notation.
If you wish to learn more about simpliy, please refer to the MathWorks documentation below:

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