Syntax problem with a user-defined function with sine

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Mhyanif
Mhyanif 2023 年 3 月 3 日
編集済み: KSSV 2023 年 3 月 3 日
Hello, I need to make this function r(𝜃) = 𝜋(3―sin^5*𝜃) as a user-defined function, but I keep getting the "Error using sin - Not enough input arguments." This is how I defined the function so far:
r(theta)=my_function(pi(3-sin.^5*theta));
How do I fix it?

回答 (1 件)

KSSV
KSSV 2023 年 3 月 3 日
編集済み: KSSV 2023 年 3 月 3 日
function r = my_function(thet)
r = pi*(3-sin(theta)^5) ;
end
Save the above, it will be saved on he name my_function.m. Or copy it under your main function code.
You can also define anonymous function as shown below:
r = @(theta) pi*(3-sin(theta)^5) ;
r(pi/2)
Note: your theta shoould be in radians. If you want theta in degrees either convert it to radians or use sind

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