Matlab bode plot with specific cut off frequency

3 ビュー (過去 30 日間)
Aaron Frost
Aaron Frost 2023 年 2 月 21 日
コメント済み: Star Strider 2023 年 2 月 21 日
This scrip displays a bode diagram however the cut off frequency is incorrect. I need the cut off frequency to be 15kHz whilst showing the gain to be 27dB. Does anyone have an idea how I can achieve this? Thank in advance.
clc
format long
C1 = 0.000000000150;
C2 = 0.000000000470;
R1 = 10000;
R2 = 180000;
R3 = 2700;
R4 = 56000;
G = (R3+R4)/R3;
A = 1/(C1*R2)
B = 1/(C2*R2)
C = (1/(C1*R1))*(1-G)
D = 1/(C1*C2*R1*R2)
E = (A+B+C)
%{
Numerator = {[G 0 0] };
Denominator = {[1 0] [A] [B] [C] [0 D]};
T = tf(Numerator, Denominator)
Numerator = {[G 0 0] };
Denominator = {[1 (A+B+C) D]};
T = tf(Numerator, Denominator)
%}
%{
T = tf([G 0 0], [1 (A+B+C) D]);
%}
%T = tf([21.740 0 0], [1 1.418439716*10^4 5.263157895*10^-6]);
T = tf([G 0 0], [1 E D]);
%T = tf([21.740740740741 0 0], [1 -13778303.125821 7880220646.1781])
options = bodeoptions;
options.FreqUnits = 'Hz'; % or 'rad/second', 'rpm', etc.
bode(T,options);
grid on
Im looking to achieve something like this.

回答 (1 件)

Star Strider
Star Strider 2023 年 2 月 21 日
The easiest option may be to define the radian frequency function:
w = linspace(0, 1.5E+4, 1E+3)*2*pi;
and then supply it as an argument to bode
clc
format long
C1 = 0.000000000150;
C2 = 0.000000000470;
R1 = 10000;
R2 = 180000;
R3 = 2700;
R4 = 56000;
G = (R3+R4)/R3;
A = 1/(C1*R2);
B = 1/(C2*R2);
C = (1/(C1*R1))*(1-G);
D = 1/(C1*C2*R1*R2);
E = (A+B+C);
%{
Numerator = {[G 0 0] };
Denominator = {[1 0] [A] [B] [C] [0 D]};
T = tf(Numerator, Denominator)
Numerator = {[G 0 0] };
Denominator = {[1 (A+B+C) D]};
T = tf(Numerator, Denominator)
%}
%{
T = tf([G 0 0], [1 (A+B+C) D]);
%}
%T = tf([21.740 0 0], [1 1.418439716*10^4 5.263157895*10^-6]);
T = tf([G 0 0], [1 E D]);
%T = tf([21.740740740741 0 0], [1 -13778303.125821 7880220646.1781])
w = linspace(0, 1.5E+4, 1E+3)*2*pi;
options = bodeoptions;
options.FreqUnits = 'Hz'; % or 'rad/second', 'rpm', etc.
bode(T,w,options);
grid on
.
  2 件のコメント
Aaron Frost
Aaron Frost 2023 年 2 月 21 日
Sorry I forgot to mention that I need to gain to be visible showing 27dB
This is what im looking to achieve but it needs to be with matlab
Star Strider
Star Strider 2023 年 2 月 21 日
Try something like this —
% clc
format long
C1 = 0.000000000150;
C2 = 0.000000000470;
R1 = 10000;
R2 = 180000;
R3 = 2700;
R4 = 56000;
G = (R3+R4)/R3;
A = 1/(C1*R2);
B = 1/(C2*R2);
C = (1/(C1*R1))*(1-G);
D = 1/(C1*C2*R1*R2);
E = (A+B+C);
%{
Numerator = {[G 0 0] };
Denominator = {[1 0] [A] [B] [C] [0 D]};
T = tf(Numerator, Denominator)
Numerator = {[G 0 0] };
Denominator = {[1 (A+B+C) D]};
T = tf(Numerator, Denominator)
%}
%{
T = tf([G 0 0], [1 (A+B+C) D]);
%}
%T = tf([21.740 0 0], [1 1.418439716*10^4 5.263157895*10^-6]);
T = tf([G 0 0], [1 E D]);
%T = tf([21.740740740741 0 0], [1 -13778303.125821 7880220646.1781])
w = logspace(-3, log10(1.5E+8), 1E+3)*2*pi;
options = bodeoptions;
options.FreqUnits = 'Hz'; % or 'rad/second', 'rpm', etc.
bode(T,w,options);
grid on
Fx = gcf;
Kids = Fx.Children;
MagPlot = Kids(3);
YdB = MagPlot.YLim
YdB = 1×2
-3.000000000000000 0.267445587351631
Ymag = db2mag(YdB)
Ymag = 1×2
0.000000000000001 21.738418068660366
.

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