optimization problem with arrays

Hello, I am trying to create a problem based optimization problem for minimazing.

To summer it up, I want to do this optimization and I don't know how to do what I have in bold:

array1 = array2 - array3 .* (optimization_variable);

A=sum(array1(array1>0));

objective = A;

Is there any way to put conditionals in an optimization problem?

Thanks in advance

Answer 1

[Bruno Luong]

Could you try this equivalent expression

A=sum(array1.*(array1>0));

[Gerard Burjalès]

Thanks for your comment but it is not working.

I think that the problem is due to the fact that it is an optimizationExpresion so the comparison doesn't work.

I am adding the error, the same I had before, that I get:

Error using ()

Subscripting into a table using one subscript (as in t(i)) is not supported. Specify a row subscript and a variable subscript, as in t(rows,vars). To select variables, use t(:,i) or for one variable t.(i). To select rows, use t(i,:).

Error in optim.internal.problemdef.display.writeExtraParams

Error in optim.problemdef.OptimizationExpression/expandNonlinearStr

Error in optim.internal.problemdef.display.showDisplay

Error in optim.problemdef.OptimizationProblem/expandObjectives2str

Error in optim.internal.problemdef.ProblemImpl/expand2str

Error in optim.internal.problemdef.ProblemImpl/showproblem

Error in optim.internal.problemdef.ProblemImpl/show

[Bruno Luong]

May be you should relax the if test and replace it with one of the sigmodid function

https://en.wikipedia.org/wiki/Sigmoid_function

S = @(x) atan(x)/(pi/2); % select the function you want
scale = ... ; small number appropriate for array1.
A = sum(array1.*((S(array1/scale)+1)/2));

[Gerard Burjalès]

Thanks for solving the issue and for the warm welcome in this community