What is the proper way to address this array when using an if-then statement with logical operators?

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zak owen 2022 年 12 月 5 日

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https://jp.mathworks.com/matlabcentral/answers/1871682-what-is-the-proper-way-to-address-this-array-when-using-an-if-then-statement-with-logical-operators

編集済み: Voss 2022 年 12 月 6 日

What is the best way to create arrays for each C1 , C2 , C3 , and C4 based off a logical if statement? The array RATN is a 6X10 array that is used in the calculation of C1-4. I would like to create a 6x10 array for each C1 , C2 , C3 , and C4 based on the index value in which if RATN is greater than 0.1 but less than 2.0 a value is calculated from one equation, but if the value is greater than 2 the value is calculated from a different equation. As I have it set up now C1 is being populated with values calculated from RATN that are greater than 2.0 with the equation that is supposed to be used for values less than 2.0.

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Answer 1

Voss 2022 年 12 月 5 日

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https://jp.mathworks.com/matlabcentral/answers/1871682-what-is-the-proper-way-to-address-this-array-when-using-an-if-then-statement-with-logical-operators#answer_1120612

MATLAB Online で開く

[m,n] = size(ratn);
C1 = zeros(m,n);
C2 = zeros(m,n);
C3 = zeros(m,n);
C4 = zeros(m,n);
idx = ratn < 2 & ratn >= 0.1;
C1(idx) = 0.947 + 1.206.*sqrr(idx) - 0.131.*ratn(idx);
C2(idx) = 0.022 - 3.405.*sqrr(idx) + 0.915.*ratn(idx);
C3(idx) = 0.869 + 1.777.*sqrr(idx) - 0.555.*ratn(idx);
C4(idx) = -0.810 + 0.422.*sqrr(idx) - 0.260.*ratn(idx);
C1(~idx) = 1.232 + 0.832.*sqrr(~idx) - 0.008.*ratn(~idx);
C2(~idx) = -3.813 + 0.968.*sqrr(~idx) - 0.260.*ratn(~idx);
C3(~idx) = 7.423 - 4.868.*sqrr(~idx) + 0.869.*ratn(~idx);
C4(~idx) = -3.839 + 3.070.*sqrr(~idx) - 0.600.*ratn(~idx);