How to create time windows given start and stop indices
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I have 2 vectors of indices: 1 for start times and 1 for end times:
>> size(trainStarts)
ans =
20 1
>> size(trainEnds)
ans =
20 1
Is there a way to, without using loops, that I can create a new variable representing windows that would be like trainStarts(1) : trainEnds(1), trainStarts(2) : trainEnds(2) and so on?
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採用された回答
Voss
2022 年 11 月 10 日
Here's one way:
trainStarts = [2 10 15];
trainEnds = [6 12 21];
result = arrayfun(@(x,y)x:y,trainStarts,trainEnds,'UniformOutput',false)
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その他の回答 (1 件)
Image Analyst
2022 年 11 月 10 日
編集済み: Image Analyst
2022 年 11 月 10 日
Yes, but why? What's wrong with having them in separate arrays.
for k = 1 : length(trainStarts)
thisRange = trainStarts(k) : trainEnds(k);
% Now do something with thisRange.
end
If you want to store/keep all the ranges separately you need to put them into cells because each range might be a different number of elements.
for k = 1 : length(trainStarts)
thisRange{k} = trainStarts(k) : trainEnds(k);
% Now do something with thisRange.
end
If you don't know what a cell array is see the FAQ:
2 件のコメント
Image Analyst
2022 年 11 月 10 日
Then use my first snippet rather than my second snippet or the answer you Accepted. No sense storing stuff you don't need to store.
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