Nul characters and wildcards in regexp
2 ビュー (過去 30 日間)
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It seems to be the case that when a regular expression encounters the pattern
[0 46 0]
it always matches everything after it.
Is this a side effect explainable in any way, or just a bug?
Example:
K>> regexp(char([0 0 1 0 41 41 41 41 41 41]),char([0 '.' 0 40 40 40 40]))
ans =
2
The expected answer would be [] because 41 should not match the 40 in the pattern.
1 件のコメント
per isakson
2015 年 3 月 23 日
編集済み: per isakson
2015 年 3 月 23 日
I call it a bug. Why not report it to tech-support whether it is a real problem to your projekt or not.
回答 (1 件)
Tijs Van Oevelen
2016 年 5 月 10 日
Hi,
this bug is probably already fixed. I tested your example in several versions of Matlab:
- in R2013b:
>> regexp(char([0 0 1 0 41 41 41 41 41 41]),char([0 '.' 0 40 40 40 40]))
ans =
2
- in R2015a:
>> regexp(char([0 0 1 0 41 41 41 41 41 41]),char([0 '.' 0 40 40 40 40]))
ans =
2
- in R2016a:
>> regexp(char([0 0 1 0 41 41 41 41 41 41]),char([0 '.' 0 40 40 40 40]))
ans =
[]
0 件のコメント
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