How permutate 2-by-2 matrices in a single matrix
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Hello everyone
I have three
matrices as:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1172308/image.png)
a = [1,2;3,4]; b = [2,5;1,6]; c = [3,7;2,4];
and collect them in a single M matrix as, M = [a,b,c]. Now I want to have permutation of these three matrices in M_P matrix as:
M_P = [a b c;
a c b;
b a c;
b c a;
c a b;
c b a].
When I use M_P = perms(M), I could not obtain the [M_P] written above. it permutation all the value inside the matirices, however I just want permutation just matrices (a,b,c) then, place the values of matrices. I would appriciate it you can help me
Thanks in advance
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採用された回答
Bruno Luong
2022 年 10 月 28 日
a = [1,2;3,4]; b = [2,5;1,6]; c = [3,7;2,4];
abc= {a,b,c};
abc=perms(abc)
abc=cell2mat(abc)
3 件のコメント
Bruno Luong
2022 年 10 月 29 日
Take a look at cellfun
It's funny that you ask to create data in format that you don't know how to work with. It is better that you don't jump quickly and think more about the data structure that you know how to manipulate downstream.
Might be what you need is 4D array and not a 2D array of all permulations clump together.
その他の回答 (1 件)
Rik
2022 年 10 月 28 日
編集済み: Rik
2022 年 10 月 28 日
You're close. You just need to store a, b, and c in a cell array and use perms to create indices.
The benefit of this approach is that you can extend it to more or fewer elements (although you will run into memory constraints fast with a larger number of matrices).
a = [1,2;3,4]; b = [2,5;1,6]; c = [3,7;2,4];
collation = {a,b,c};
inds = perms(1:numel(collation))
M_P = collation(inds)
M_P = cell2mat(M_P)
7 件のコメント
Bruno Luong
2022 年 10 月 29 日
a = [1,2;3,4]; b = [2,5;1,6]; c = [3,7;2,4];
abc= {a,b,c};
abc=perms(abc);
2*abc{1,1}
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