Array values assigned to for loop

t = truss(X, edges, k)
% t: tension in edges

t = [-0.5 ; 1.5811 ; -1.5811]

% yield strength
sigmay = 0.3;
A = edgeArea;
T = sigmay .* A;
N=1;
for i = t(N):t(N+1,:)
    if i > 0 ; i < T;
        disp(i)
        disp('edge does not yield')
    elseif i > T;
        disp(i)
        disp('edge yeilds')
    else i < 0;
        disp(i)
        disp('edge is negative, check buckle')
    end
end

I want to run the code so the value of t(1) [-0.5] is ran and solved and displayed then t(2) [1.5811] is and then finally t(3) [-1.5811].

Answer 1

[Eric Delgado]

Try this...

t = [-0.5; 1.5811; -1.5811];
T = 1;

for i = 1:numel(t)
    if t(i) > 0 & t(i) < T
        msg = 'edge does not yield';
    elseif t(i) > T
        msg = 'edge yeilds';
    else
        msg = 'edge is negative, check buckle';
    end
    
    fprintf('%.4f - %s\n', t(i), msg)
end

-0.5000 - edge is negative, check buckle
1.5811 - edge yeilds
-1.5811 - edge is negative, check buckle